(16-x²)+(4-x) or (-x²+16)+(-x+4)
Combine like terms
(-x²+20-x) or (-x²-x+20)
<span>A polynomial with the given zeros can be represented as
f(x) = (x-1)(x-2)(x+2)(x+3).
Note that if you set f(x) = 0, then 1,2,-2, and -3 certainly are the solutions. From here, we simply multiply/expand out the polynomial. We can do this in a variety of ways, one of which is taking the left two and right two products separately. We have
(x-1)(x-2) = x^2 - 3x + 2
and
(x+2)(x+3) = x^2 + 5x + 6.
This gives that
f(x) = (x^2 - 3x + 2) (x^2 + 5x + 6).
Expanding this expression out then gives us our answer as
f(x) = x^4 + 2x^3 - 7x^2 - 8x + 12
or answer choice B.</span>
Answer:
B' (-4, -4)
Step-by-step explanation:
When you dilate from the origin, you multiply the coordinate points by the scale factor.
B (-1, -1) × 4 = B' (-4, -4)
I hope this helps :))
Answer: The answer is x >7
Step-by-step explanation:
56⋅x>616−224
56⋅x>616-224
Simplify :
56⋅x>392
56⋅x>392
Dividing by the variable coefficient :
x>
392
56
x>39256
Simplify :
x>7
x>7
Inequality
56⋅x+224>616
56⋅x+224>616
is true for
x>7
x>7
