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Lisa [10]
3 years ago
11

8x1 = 8

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
8 0
The correct answer is B
NeTakaya3 years ago
8 0
The answer to this problem is B
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Fine lowest common values for x and y variables of A[4x - 7y = 2] <br> B[3x - 3y = 6]
OLEGan [10]

3x -3y = 6

or, 3(x -y)= 6

or, x-y =6/3

or, x-y = 2

or, x=2+y........eqn(i)

4x - 7y = 2

substituting the value of x from eqn(i)

or, 4(2+y) -7y = 2

or, 8 + 4y -7y = 2

or, -3y = 2-8

or, y = -6/-3

■ y=2

so in eqn(i)

x= 2+y

x= 2+2

■x = 4

3 0
3 years ago
Clara is completing a Math project. She has two ropes with lengths 126 cm and 291 cm. She wants to cut them into pieces of equal
Wewaii [24]

Answer:

3

Step-by-step explanation:

if she can cut the 126 cm length rope into 42 pieces and 291 cm rope into 97 pieces she will have no remainders

42*3=126

97*3=291

7 0
3 years ago
8% of 195 is what number
meriva

Answer:

15.6

Step-by-step explanation:

Hope this helps

-A Helping Friend

3 0
3 years ago
Read 2 more answers
In 1 minute, Alex can type 44 words. While working on a project, Alex types from 10:00 AM until 1 AM, He takes a break from 1 0:
viktelen [127]

Answer:

39600 words

Step-by-step explanation:

Given data

In 1 minute, Alex can type 44 words

from 10:00 AM until 1 AM= 15 hours

15 hours to minutes= 15*60= 900 minutes

Hence in In 1 minute, Alex can type 44 words

            in  900 minutes he will type x words

cross multiply

x= 900*44

x= 39600 words

Hence he will type 39600 words

4 0
3 years ago
The distribution of the number of viewers for the American Idol television show follows a normal distribution with a mean of 26
hjlf

Answer:

Probability that next week's show will have between 30 and 37 million viewers is 0.2248.

Step-by-step explanation:

We are given that the distribution of the number of viewers for the American Idol television show follows a normal distribution with a mean of 26 million with a standard deviation of 8 million.

<em>Let X = number of viewers for the American Idol television show</em>

So, X ~ N(\mu=26,\sigma^{2}=8^{2})

Now, the z score probability distribution is given by;

          Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = population mean = 26 million

            \sigma = standard deviation = 8 million

So, probability that next week's show will have between 30 and 37 million viewers is given by = P(30 < X < 37) = P(X < 37) - P(X \leq 30)

    P(X < 37) = P( \frac{X-\mu}{\sigma} < \frac{37-26}{8} ) = P(Z < 1.38) = 0.91621

    P(X \leq 30) = P( \frac{X-\mu}{\sigma} \leq \frac{30-26}{8} ) = P(Z \leq 0.50) = 0.69146

<em>Therefore, P(30 < X < 37) = 0.91621 - 0.69146 = 0.2248</em>

Hence, probability that next week's show will have between 30 and 37 million viewers is 0.2248.

4 0
3 years ago
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