Ask question

Ask question

All categories

tamaranim1 [39]

2 years ago

14

recycling one metric ton of corrugated cardboard will sAVE ABOUT 17 TREES. a WAREHOUSE RECYCLED 14,327 KILOGRAMS OF CORRUGATED C

ARDBOARD OVER THE LAST YEAR. hOW MANY TREES DID THIS SAVE.

2 answers:

melomori [17]2 years ago

8 0

Answer:

243 trees were saved.

Step-by-step explanation:

Recycling one metric ton (1000 kg) of corrugated cardboard will save number of trees = 17

Warehouse recycled 14327 kg of cardboard last year. So we have to find the number of trees saved.

To find the number of trees we will use the unitary method.

∵ Recycling 1000 kg of cardboard number of trees saved = 17

∴ Recycling 1 kg cardboard number of trees saved = $\frac{17}{1000}$

∴ 14327 kg cardboard will save the number of trees = $\frac{17}{1000}\times 14327$

= 243.559

≈ 243 trees

Therefore, 243 trees were saved.

slega [8]2 years ago

3 0

1 kg = 0.001 metric tons..so 14327 kg = (14327 * 0.001) = 14.327 metric tons
and if 1 metric tons saves 17 trees....then 14.327 tons saves : 14.327 * 17 = 243.559 saved trees...and since u cant have 0.559 trees, u would round to 243 trees

You might be interested in

How many lines of symmetry does this figure have?

Gnom [1K]

Answer:

4

Step-by-step explanation:

split it horizontally, vertically and diagonally twice.

8 0

3 years ago

Read 2 more answers

Drag each tile to the correct box.

kolbaska11 [484]

Answer:

a) Distance between points A (5, 4) and B( 5, -2) is 6 unitsb) Distance between points E (-2, -1) and F( -2, -5) is 4 unitsc) Distance between points C (-4, 1) and D( 1, 1) is 5 unitsd) Distance between points G(3, -5) and H(6, -5) is 3 unitsStep-by-step explanation:We need to find the distance between each paira) A (5, 4) and B( 5, -2)

Step-by-step explanation:

8 0

2 years ago

What is the y-intercept of the graph of the equation y=4x(3x) A; (0,4) B: (0,3) C;(0,12) D:(0,8)

Alchen [17]

Answer:

To find y intercept x should be 0.

And in this.

Y=4x.3x

Y=4*0*3*0

Y=0 answer.

4 0

2 years ago

Can someone check whether its correct or no? this is supposed to be the steps in integration by parts

Gwar [14]

Answer:

$\displaystyle - \int \dfrac{\sin(2x)}{e^{2x}}\: \text{d}x=\dfrac{\sin(2x)}{4e^{2x}}+\dfrac{\cos(2x)}{4e^{2x}}+\text{C}$

Step-by-step explanation:

$\boxed{\begin{minipage}{5 cm}\underline{Integration by parts} \\\\$\displaystyle \int u \dfrac{\text{d}v}{\text{d}x}\:\text{d}x=uv-\int v\: \dfrac{\text{d}u}{\text{d}x}\:\text{d}x$ \\ \end{minipage}}$

Given integral:

$\displaystyle -\int \dfrac{\sin(2x)}{e^{2x}}\:\text{d}x$

$\textsf{Rewrite }\dfrac{1}{e^{2x}} \textsf{ as }e^{-2x} \textsf{ and bring the negative inside the integral}:$

$\implies \displaystyle \int -e^{-2x}\sin(2x)\:\text{d}x$

Using <u>integration by parts</u>:

$\textsf{Let }\:u=\sin (2x) \implies \dfrac{\text{d}u}{\text{d}x}=2 \cos (2x)$

$\textsf{Let }\:\dfrac{\text{d}v}{\text{d}x}=-e^{-2x} \implies v=\dfrac{1}{2}e^{-2x}$

Therefore:

$\begin{aligned}\implies \displaystyle -\int e^{-2x}\sin(2x)\:\text{d}x & =\dfrac{1}{2}e^{-2x}\sin (2x)- \int \dfrac{1}{2}e^{-2x} \cdot 2 \cos (2x)\:\text{d}x\\\\& =\dfrac{1}{2}e^{-2x}\sin (2x)- \int e^{-2x} \cos (2x)\:\text{d}x\end{aligned}$

$\displaystyle \textsf{For }\:-\int e^{-2x} \cos (2x)\:\text{d}x \quad \textsf{integrate by parts}:$

$\textsf{Let }\:u=\cos(2x) \implies \dfrac{\text{d}u}{\text{d}x}=-2 \sin(2x)$

$\textsf{Let }\:\dfrac{\text{d}v}{\text{d}x}=-e^{-2x} \implies v=\dfrac{1}{2}e^{-2x}$

$\begin{aligned}\implies \displaystyle -\int e^{-2x}\cos(2x)\:\text{d}x & =\dfrac{1}{2}e^{-2x}\cos(2x)- \int \dfrac{1}{2}e^{-2x} \cdot -2 \sin(2x)\:\text{d}x\\\\& =\dfrac{1}{2}e^{-2x}\cos(2x)+ \int e^{-2x} \sin(2x)\:\text{d}x\end{aligned}$

Therefore:

$\implies \displaystyle -\int e^{-2x}\sin(2x)\:\text{d}x =\dfrac{1}{2}e^{-2x}\sin (2x) +\dfrac{1}{2}e^{-2x}\cos(2x)+ \int e^{-2x} \sin(2x)\:\text{d}x$

$\textsf{Subtract }\: \displaystyle \int e^{-2x}\sin(2x)\:\text{d}x \quad \textsf{from both sides and add the constant C}:$

$\implies \displaystyle -2\int e^{-2x}\sin(2x)\:\text{d}x =\dfrac{1}{2}e^{-2x}\sin (2x) +\dfrac{1}{2}e^{-2x}\cos(2x)+\text{C}$

Divide both sides by 2:

$\implies \displaystyle -\int e^{-2x}\sin(2x)\:\text{d}x =\dfrac{1}{4}e^{-2x}\sin (2x) +\dfrac{1}{4}e^{-2x}\cos(2x)+\text{C}$

Rewrite in the same format as the given integral:

$\displaystyle \implies - \int \dfrac{\sin(2x)}{e^{2x}}\: \text{d}x=\dfrac{\sin(2x)}{4e^{2x}}+\dfrac{\cos(2x)}{4e^{2x}}+\text{C}$

5 0

1 year ago

How do you find x? and how do you round to the nearest tenth?

expeople1 [14]

Hey there!

In order to solve this problem, we can use the Pythagorean Theorem, which is $c^2 = a^2 + b^2$ . Since the Pythagorean Theorem would find only half of the length of x, we'll need to double it in the end.

First, let's plug in what we know to the Pythagorean Theorem: $2.1^2 = 1.4^2 + b^2$

Next, we'll simplify to that $b^2$ is by itself:

$b^2 = 2.45$

Then, we'll find the square root of 2.45, multiply that by 2 and round to the nearest tenth:

$2(\sqrt{2.45} ) = 3.1$

Therefore, x = 3.1 ft.

How to round to the nearest tenth:

In a decimal, the tenth is the first number after the decimal point. To round to the tenth, if the number in the hundredth place is less than 5, you keep the number as it is, but if the number in the hundredth place is more than 5, you increase the number in the tenth place by 1.

Hope this helps!! :)

6 0

2 years ago