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2 years ago

I NEED HELP PLEASEEEEEEEEEEE

Mathematics

2 answers:

RoseWind [281]2 years ago

6 0

Answer:

2x + 4y = 12 and y = -1/2x + 3

Ratling [72]2 years ago

5 0

2x +4y=12 and y=-1/2+3

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Write the equation in slope intercept form of the line that passes through the point (1,-3) and a slope of -2

Alborosie

Answer:y=-2x-1

Step-by-step explanation:

(1,-3) and a slope of -2

Use Formula

Y= mx +b to find b. By using the slope and point given .

M is slope

Y is -3

X Is 1

Y=mx+b

-3= -2(1)+b

-3= -2+b

-3+2=b

-1=b

Now create the equation by inputting the slope they gave you which is -2 and answer we solved for b which is -1 .

Y= -2x-1

4 0

3 years ago

Will award brainliest to correct answer!

Artyom0805 [142]

Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.

$\angle \: ABP = \frac{180 - 80}{2} = 50 \degree$

Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.

Therefore, the angle BKQ is equal to 180-50-45=85°.

Of course angle BKP=180-85=95°.

Hope this helps :)

6 0

2 years ago

Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th

trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

t = 20: 999 fishes

t = 30: 1168 fishes

(c)

$P(\infty) = 1200$

Step-by-step explanation:

Given

$P(t) =\frac{d}{1+ke^-{ct}}$

$d = 1200\\k = 11\\c=0.2$

Solving (a): Fishes at t = 0

This gives:

$P(0) =\frac{1200}{1+11*e^-{0.2*0}}$

$P(0) =\frac{1200}{1+11*e^-{0}}$

$P(0) =\frac{1200}{1+11*1}$

$P(0) =\frac{1200}{1+11}$

$P(0) =\frac{1200}{12}$

$P(0) = 100$

Solving (a): Fishes at t = 10, 20, 30

$t = 10$

$P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483$

$t = 20$

$P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999$

$t = 30$

$P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168$

Solving (c): $\lim_{t \to \infty} P(t)$

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of $e^{-ct}$ decreases

This implies that:

${t \to \infty} = {e^{-ct} \to 0}$

So:

The value of P(t) for large values is:

$P(\infty) = \frac{1200}{1 + 11 * 0}$

$P(\infty) = \frac{1200}{1 + 0}$

$P(\infty) = \frac{1200}{1}$

$P(\infty) = 1200$

5 0

2 years ago

Kaitlyn is walking on a treadmill at a constant pace for 28 minutes. She has programmed the treadmill for a 2-mile walk. The dis

maw [93]

Is this multiplying or what??? Anyways try calculating those numbers so basically you need to calculate 28x2 or if you have to divide them or multiply them you would get the answer is very simple

6 0

2 years ago

Solve the system of equation by the addition method x-2y=11 and -x+6y =-31

Sonbull [250]

Answer: x = 1, y = - 5

Step-by-step explanation:

The given system of linear equations is expressed as

x - 2y = 11- - - - - - - - - - - - -1

- x + 6y = - 31- - - - - - - - - - - -2

We would eliminate x by adding equation 1 to equation 2. It becomes

- 2y + 6y = 11 - 31

4y = - 20

Dividing the the left hand side and the right hand side of the equation by 4, it becomes

4y/4 = - 20/4

y = - 5

Substituting y = - 5 into equation 1, it becomes

x - 2 × - 5 = 11

x + 10 = 11

Subtracting 10 from the left hand side and the right hand side of the equation, it becomes

x + 10 - 10 = 11 - 10

x = 1

3 0

3 years ago