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photoshop1234 [79]

3 years ago

12

What is the difference of the two expressions shown below? (3/4x + 2) - (1/4x + 5)

1 answer:

faltersainse [42]3 years ago

5 0

Answer:

-4. (e) (2-7)(5–3)+32. (-5)(2) +9. -10+9. -8710. 913 - 12 - 13. Ex: Evaluate 4x-7 when x=5. 4(5)-7 ... Ex: In the following exercise we show how two linear expressions are ... equivalency of the two expressions you determined to be equivalent above? ... Ex: Determine an expression that is equivalent to 10x+15? lox+1. 5(2X+3).

Step-by-step explanation:

Here is my notes hope it helped

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3 years ago

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Use a 10-by-10 grid to model the percent.<br> 1. 43%

JulsSmile [24]

Answer:

I diminished the amount that

Step-by-step explanation:

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3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B2x%7D%7Bx%2B1%7D%20%2B%5Cfrac%7B3%28x-1%29%7D%7Bx%7D%20%3D5" id="TexFormula1" title=

Luden [163]

Answer:

$x=-3$

Step-by-step explanation:

<u>Given equation</u>:

$\dfrac{2x}{x+1}+\dfrac{3(x+1)}{x}=5$

Make the <u>denominators</u> the same:

$\implies \dfrac{2x}{x+1} \cdot\dfrac{x}{x}+\dfrac{3(x+1)}{x} \cdot \dfrac{x+1}{x+1}=5$

$\implies \dfrac{2x^2}{x(x+1)}+\dfrac{3(x+1)^2}{x(x+1)} =5$

<u>Combine</u> the fractions:

$\implies \dfrac{2x^2+3(x+1)^2}{x(x+1)} =5$

<u>Multiply</u> both sides by x(x+1):

$\implies 2x^2+3(x+1)^2 =5x(x+1)$

<u>Expand</u> the brackets:

$\implies 2x^2+3(x^2+2x+1) =5x^2+5x$

$\implies 2x^2+3x^2+6x+3 =5x^2+5x$

<u>Combine</u> like terms:

$\implies 5x^2+6x+3=5x^2+5x$

<u>Subtract</u> 5x² from both sides:

$\implies 6x+3=5x$

<u>Subtract</u> 5x from both sides:

$\implies x+3=0$

<u>Subtract</u> 3 from both sides:

$\implies x=-3$

Learn more about algebraic fractions here:

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5 0

2 years ago

A college student is taking two courses. The probability she passes the first course is 0.67. The probability she passes the sec

andrezito [222]

Answer:

0.58 = 58% probability she passes both courses

Step-by-step explanation:

We can solve this question treating the probabilities as a Venn set.

I am going to say that:

Event A: She passes the first course.

Event B: She passes the second course.

The probability she passes the first course is 0.67.

This means that $P(A) = 0.67$

The probability she passes the second course is 0.7.

This means that $P(B) = 0.7$

The probability she passes at least one of the courses is 0.79.

This means that $P(A \cup B) = 0.79$

a. What is the probability she passes both courses

This is $P(A \cap B)$ .

We use the following relation:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

So

$P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.67 + 0.7 - 0.79 = 0.58$

0.58 = 58% probability she passes both courses

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3 years ago

riangle ABC is a right triangle. What is the relationship between angles A and B? They are congruent. They are complementary. Th

iragen [17]

I think it maybe be <span>complementary</span>, sorry I'm not completely sure but i hope this helps.

7 0

3 years ago