Answer:
Consider this: factors that are the same that are in the numerator and denominator of a fraction cancel out.
e.g. 20/30 = [2(10)]/[3(10)] = 2/3 This is because the 10 present in the numerator exactly equals the 10 present in the denominator.
We can use the above principle for these types of problems!
If the projectile is fired at 422 mi/hr, and we want to convert this speed into m/s, we just need to go through the following process:
422 mi/hr * 1610m/1mi * 1hr/60min * 1min/60s = 189 m/s
Step-by-step explanation:
Answer:
Step-by-step explanation:
J = (1/3)M + 2 <=== ur expression would be : (1/3)M + 2
A = 2J - 5
if marcella is 63....
J = (1/3 * 63) + 2 A = 2J - 5
J = 63/3 + 2 A = 2(23) - 5
J = 21 + 2 A = 46 - 5
J = 23 <== justin's age A = 41 <=== Aimee's age
Answer:
IM TERRIBLE IN GEOMETRY
Step-by-step explanation:
Answer:
Below.
Step-by-step explanation:
f) (a + b)^3 - 4(a + b)^2
The (a+ b)^2 can be taken out to give:
= (a + b)^2(a + b - 4)
= (a + b)(a + b)(a + b - 4).
g) 3x(x - y) - 6(-x + y)
= 3x( x - y) + 6(x - y)
= (3x + 6)(x - y)
= 3(x + 2)(x - y).
h) (6a - 5b)(c - d) + (3a + 4b)(d - c)
= (6a - 5b)(c - d) + (-3a - 4b)(c - d)
= -(c - d)(6a - 5b)(3a + 4b).
i) -3d(-9a - 2b) + 2c (9a + 2b)
= 3d(9a + 2b) + 2c (9a + 2b)
= 3d(9a + 2b) + 2c (9a + 2b).
= (3d + 2c)(9a + 2b).
j) a^2b^3(2a + 1) - 6ab^2(-1 - 2a)
= a^2b^3(2a + 1) + 6ab^2(2a + 1)
= (2a + 1)( a^2b^3 + 6ab^2)
The GCF of a^2b^3 and 6ab^2 is ab^2, so we have:
(2a + 1)ab^2(ab + 6)
= ab^2(ab + 6)(2a + 1).
