Answer:
5 and 6
Step-by-step explanation:
The square root of 27 is 5.19615242271 , which is more than 5 but less then 6, therefore is between 5 and 6.
<em />
<em />
<em />
<em />
<em />
<em />
<em>Hope this helped (: Can you please mark as brainliest?</em>
Answer:
The restrictions will be:
x ≠ 0;
x² ≠ 0 ⇒ x ≠ 0 ;
5x² ≠ 0 ⇒ x² ≠ 0 ⇒ x ≠ 0;
Step-by-step explanation:
As we know that
There are two genuine reasons why domains are restricted.
We cannot divide the expression by 0 as it would be undefined then.
We cannot take the square root of a negative number, as the result will not be a defined.
Considering the expression
![\frac{4}{x}+\frac{1}{x^2}=\frac{1}{5x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7Bx%7D%2B%5Cfrac%7B1%7D%7Bx%5E2%7D%3D%5Cfrac%7B1%7D%7B5x%5E2%7D)
As we can not put x = 0 in the denominator as it would make the expression undefined.
In other words, the certain values which make the denominator equal to zero for a rational expression will be restricted values.
Hence, the restrictions will be:
x ≠ 0;
x² ≠ 0 ⇒ x ≠ 0 ;
5x² ≠ 0 ⇒ x² ≠ 0 ⇒ x ≠ 0;
Answer:
Starting with AT LEAST 2 A's means starting with 3 A's, or starting with 2 A's with some different letter third.
P(AAA...) = (3/9)(2/8)(1/7) = 1/84
Step-by-step explanation:
Consider, pls, this option (see the attachment) of 3 steps.
Answer:
Yes
Step-by-step explanation:
5/2 is an improper fraction which can be written as 2 1/2 ie 2 and a half. 2 is greater than 1. Clearly 2 1/2 is greater than 1. Therefore 5/2 is greater than 1