Question

red-green color blindness is an x-linked recessive disorder. if the mother is RGCB and the father has normal vision, what are the changes for daughters and sons to hae the trait

Answer 1

Answer:

The correct answer would be -

RGCB daughter - 0%

RGCB sons - 100%

Explanation:

Red-green color blindness is a sex-linked recessive disease that means it will only express in absence of the normal allele that is present on X-chromosomes. As it is known that males have only one X-chromosomes therefore, the chances are more in males to be affected in presence of the recessive gene. In this given case women s RGCB and man has normal vision. The genotype of women would be both recessive alleles XcXc and genotype of man would be XY.

The gametes would be - Xc, Xc and X, Y

then the cross:

       Xc     Xc

X     XXc    XXc

Y    XcY      XcY

so the offspring would be -

Carrier female =  XXc (50% chance in total and 100% in daughters)

RGCB daughters = 0%

RGCB male =  XcY (100% in sons and 50% of total children)