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vitfil [10]
2 years ago
14

A jeweler wants to make 14 grams of an alloy that is precisely 75% gold.. The jeweler has alloys that are 25% gold, 50% gold, &a

mp; 82% gold. Choose 2 different alloys that can be used to create one that is 75% gold. pls try to explain with a system of equations ; ;
Mathematics
1 answer:
Goryan [66]2 years ago
3 0

Given that the jeweler has alloys that are 25% gold, 50% gold, and 82% gold.

As he wants to make 14 grams of an alloy by adding two different alloys that is precisely 75% gold, so one alloy must have a percentage of gold more than 75%.

One alloy is 82% gold and, the second can be chosen between 25% gold, 50% gold, so there are two cases.

Case 1: 82% gold + 50% gold

Let x grams of 82% gold and y  grams of 50% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 50% of y

\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times y \\\\

\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times (14-x)  [as x+y=14]

\Rightarrow 75 \times 14 = 82 \times x + 50 \times (14-x)  \\\\\Rightarrow 75 \times 14 = 82 \times x + 50 \times14-50\times x \\\\\Rightarrow 75 \times 14 = 32 \times x + 50 \times14 \\\\\Rightarrow 32 \times x =75 \times 14 - 50 \times14 \\\\

\Rightarrow x =(25 \times 14)/32=10.9375 grams

and y = 14-x= 14-10.9375=3.0625 grams.

Hence, 10.9375 grams of 82% gold and 3.0625  grams of 50% gold added to make 14 grams of 75% gold.

Case 2: 82% gold + 25% gold

Let x grams of 82% gold and y  grams of 25% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 25% of y

\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times y \\\\\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times (14-x) \\\\ \Rightarrow 75 \times 14 = 82 \times x + 25 \times (14-x)  \\\\\Rightarrow 75 \times 14 = 82 \times x + 25 \times14-25\times x \\\\\Rightarrow 75 \times 14 = 57 \times x + 25 \times14 \\\\\Rightarrow 57 \times x =75 \times 14 - 25 \times14 \\\\

\Rightarrow x =(50 \times 14)/57=12.28 grams

and y = 14-x= 14-12.28=1.72 grams.

Hence, 12.28 grams of 82% gold and 1.72  grams of 50% gold added to make 14 grams of 75% gold.

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cot(<em>θ</em>) = cos(<em>θ</em>)/sin(<em>θ</em>)

So if both cot(<em>θ</em>) and cos(<em>θ</em>) are negative, that means sin(<em>θ</em>) must be positive.

Recall that

cot²(<em>θ</em>) + 1 = csc²(<em>θ</em>) = 1/sin²(<em>θ</em>)

so that

sin²(<em>θ</em>) = 1/(cot²(<em>θ</em>) + 1)

sin(<em>θ</em>) = 1 / √(cot²(<em>θ</em>) + 1)

Plug in cot(<em>θ</em>) = -2 and solve for sin(<em>θ</em>) :

sin(<em>θ</em>) = 1 / √((-2)² + 1)

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6 0
2 years ago
P viuen
Alex787 [66]
Hello what do you exactly need help for
3 0
3 years ago
The manager went over the sales of mobile phones at the store and found that the mean sale was 45, with a standard deviation of
d1i1m1o1n [39]

The z-score of the sale of mobile phones on that day is 1.75

Step-by-step explanation:

The formula of z-score is z = (x - μ)/σ, where:

  • x is the score
  • μ is the mean
  • σ is the standard deviation

∵ The mean sale was 45

∴ μ = 45

∵ The standard deviation was 4

∴ σ = 4

∵ 52 mobile phones were sold on a particular day

∴ x = 52

To find z-score of the sale of mobile phones on that day substitute the values of x, μ, and σ in the formula of z-score

∵ z=\frac{52-45}{4}

∴ z=\frac{7}{4}

∴ z = 1.75

The z-score of the sale of mobile phones on that day is 1.75

Learn more:

You can learn more about z-score in brainly.com/question/7207785

#LearnwithBrainly

3 0
3 years ago
Amanda, Boris, and Jose sent a total of 124 text messages during the weekend. Amanda sent 8 fewer messages than Jose
GrogVix [38]

Answer:

Amanda= 14

Boris = 88

Jose= 22

Step-by-step explanation:

Amanda= jose-8

Boris = 4×jose

Jose= Jose

total all = 124

(jose-8)+(jose×4)+(jose)= 124

so we substitute jose with X .

(X-8)+(4X)+(X)=124

6X-8= 124.

6X=124+8

X=132/6

X= 22.

so that total jose is 22, minus 8 we get Amanda, times 4 we get Boris.

7 0
2 years ago
2/10times6/10. Please help
babunello [35]

Answer:

I believe the answer is 1 2/10

Hope this helps!



8 0
3 years ago
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