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Debora [2.8K]
2 years ago
11

There are 10 large fish and 5 small fish. Half of the large fish are red. One fish is selected at random. Find the probability t

hat it is a large, red fish.
Mathematics
1 answer:
Softa [21]2 years ago
3 0
The probability of choosing a large red fish is 5/15 or 1/3
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A scale drawing has a scale of 1/4 in. :6ft.find the length of the drawing for each actual length.
solmaris [256]

Answer:

2 3/4 in.

Step-by-step explanation:

66/6 = 11

11(1/4) = 11/4

11/4 = 2 3/4

7 0
3 years ago
A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Kar
ch4aika [34]

Answer:

We conclude that the mean waiting time is less than 10 minutes.

Step-by-step explanation:

We are given that a public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes.

Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.8 minutes with a standard deviation of 2.5 minutes.

Let \mu = <u><em>mean waiting time for bus number 14.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 10 minutes      {means that the mean waiting time is more than or equal to 10 minutes}

Alternate Hypothesis, H_A : \mu < 10 minutes    {means that the mean waiting time is less than 10 minutes}

The test statistics that would be used here <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean waiting time = 7.8 minutes

             s = sample standard deviation = 2.5 minutes

             n = sample of different occasions = 18

So, <u><em>test statistics</em></u> =  \frac{7.8-10}{\frac{2.5}{\sqrt{18} } }  ~ t_1_7

                              =  -3.734

The value of t test statistics is -3.734.

Now, at 0.01 significance level the t table gives critical value of -2.567 for left-tailed test.

Since our test statistic is less than the critical value of t as -3.734 < -2.567, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the mean waiting time is less than 10 minutes.

5 0
3 years ago
2 1/2 ÷ 1 5/8 =<br><br> Two and a half divided by one and five eights
LUCKY_DIMON [66]
So first of all we can't start by changing them both into improper fractions

So it would be:
5/2 divided by 13/8
From there you would do 5/2 * 8/13 which could convert to
5/1 * 4/13 which would be 20/13
3 0
3 years ago
Read 2 more answers
What is the volume in the tank after two hours of the pumps running v(t)= 65t + 280
alina1380 [7]

Answer:

imma look this up rq

Step-by-step explanation:

4 0
2 years ago
I need help on this math problem?​
Licemer1 [7]

Answer:

A thend D

Step-by-step explanation:

6 0
3 years ago
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