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3 years ago

Simülasyon yayıncılık 2.gün modülü cevapları

Mathematics

1 answer:

kirza4 [7]3 years ago

5 0

Answer:

ftcgbuvyvj0miby unkmi ub8

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Can someone help me out plz

jasenka [17]

Each corner angle of a square is 90 degrees.

This means every 90 degree rotation ( Counter clockwise) would move A to the next corner.

Since B is the corner below A, it would take a 90 degree rotation fr A to map on B.

7 0

3 years ago

Can somebody help. 7 out of 10 is what percent?

Otrada [13]

Answer:

70%

Step-by-step explanation:

Multiply by ten and you get your percent

3 0

3 years ago

Read 2 more answers

Which answer describes the calculations that could be used to solve this problem?

faltersainse [42]

D. Since we know that 1 ticket = $8 we would multiply to figure out how much 7 tickets were. (7x$8). And to figure out his change you would subtract the ticket amount from $100 :) Hope this helps

4 0

3 years ago

Read 2 more answers

assume that when adults with smartphones are randomly selected 15 use them in meetings or classes if 15 adult smartphones are ra

Tanzania [10]

Answer:

The probability that at least 4 of them use their smartphones is 0.1773.

Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = <em>Number of adults who use their smartphones</em>

The above situation can be represented through the binomial distribution;

$P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......$

where, n = number of trials (samples) taken = 15 adult smartphones

r = number of success = at least 4

p = probability of success which in our question is the % of adults

who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X $\geq$ 4)

P(X $\geq$ 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= $1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}$

= $1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})$

= <u>0.1773</u>

3 0

4 years ago

A market sells 6 cans of food for every 7 boxes of food. The market sold a total of 26 cans and boxes today. How many

mamaluj [8]

Option 2 is the correct answer

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3 years ago

Simülasyon yayıncılık 2.gün modülü cevapları​

Simülasyon yayıncılık 2.gün modülü cevapları