F(x)=3x+1 (preimage)
g(x)=x+1 (image)
it is undergoing a reduction/compression with translation.
In general, a linear transformation is
g(x) = a*f(bx-h)+k
h=horizontal translation (right if h>0, left if h<0, note formula has minus sign)
k=vertical translation (up if k>0, down if k<0)
a=vertical stretching, (stretching if |a|>1, compression if |a|<1, also, if a<0, a reflection across the x-axis is performed)
b=horizontal stretching (|b|>0 compression, |b|<0 stretching, also, if b<0, a reflection across the y-axis is performed)
In this case,
g(x)=f(x/3), so it is a horizontal stretching.
Note that the y-intercept remains unchanged.
Answer:
2.5 second
Step-by-step explanation:
The equation is missing in the question.
The equation is, 
, where 'h' is the height and 't' is time measured in second.
Now we know to reach its maximum height, h in t seconds, the derivative of h with respect to time t is given by :
Now the differentiating the equation with respect to time t, we get
For maximum height,
So, 
Therefore, the ball takes 2.5 seconds time to reach the maximum height.
Yes because if you divide 4 by 67 you get about 0.0597 and if you divide 5 by 777 then you get about 0.0064 and 0.0597 is greater than 0.0064
Answer:
56 + 53pi
Step-by-step explanation:
<u><em>Area of small circles:</em></u>
diameter of small circle: 4cm
forumla to find area of circle: A = pir^2
r is radius = half of diameter -> d/2 = 4 / 2 = 2cm
A = pi (2cm)^2
A = pi (4cm)
A = 4pi
<u><em>Area of large circle:</em></u>
diameter of small circle: 4cm
forumla to find area of circle: A = pir^2
r is radius = half of diameter -> d/2 = 14 / 2 = 7cm
A = pi (7cm)^2
A = pi (49cm)
A = 49pi
<u><em>Area of rectangle:</em></u>
Area = width x length
Area = 14cm x 4cm
Area = 56cm
<u><em>Add all three areas:</em></u>
Area of rectangle + large circle + small circle
56cm + 49pi + 4pi = 56cm + 53pi
