Question

Given the function ƒ(x) = 3x + 5, find ƒ(4) and x such that ƒ(x) = 38.

Answer 1

Answer: A.17;11

f(4)= 3(4) + 5

=12 + 5

=17

And, f(x)= 38

=>3x+5=38

=>3x= 38-5

=>3x=33

=>x = 33÷3

=>x = 11

So, A.17;11