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Klio2033 [76]
3 years ago
12

Using the variable x for unknown number what is five more than the quotient of a number and 6 equals 7

Mathematics
1 answer:
Kitty [74]3 years ago
8 0

Answer:

x = 12

Step-by-step explanation:

"Using the variable x for unknown number what is five more than the quotient of a number and 6 equals 7" translates into  5 + x/6 = 7.

To solve use inverse operations.

5 + \frac{x}{6} = 7\\\\\frac{x}{6} = 2 \\\\ x = 12

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Since 19 is a prime number it is not divisible by 2. So its only divisible numbers are 1 and 19 itself. So 19 multiplied by 1 equals 1
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PolarNik [594]
The answer is $911.68.

After a little research on the internet, I found the design of the window.
First, you need to find the area of the window which is a composite figure made up of a rectangle and a circle. So, the total area (A) is the sum of the area of the rectangle (A1) and the area of the circle (A2).

Area of the rectangle with length l and width w is:
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According to the image, l = 5 ft and w = 4 ft.
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According to the image, r = 2 ft.
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A = A1 + A = 20 ft² + 12.56 ft² = 32.56 ft²

<span>The glass costs $28 per square foot, so to replace the glass will cost:
</span>32.56 ft² * $28/ft² = $911.68
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3 years ago
Can some help me answer this question ASAP
Maru [420]

Answer:

A

Step-by-step explanation:

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Simplify each expression. Assume that all variables are positive.
kozerog [31]
Q1. The answer is  \frac{8x^{3}y^{6}  }{27}

( \frac{16 x^{5} y^{10}}{81x y^{2} } )^{ \frac{3}{4} }= ( \frac{16}{81}* \frac{ x^{5} }{x}* \frac{ y^{10} }{y^{2}}   )^{ \frac{3}{4} } \\  \\ &#10;  \frac{ x^{a} }{ x^{b} }= x^{a-b}  \\  \\ &#10;( \frac{16}{81}* \frac{ x^{5} }{x}*\frac{ y^{10} }{y^{2}}   )^{ \frac{3}{4} }}=( \frac{16}{81 }* x^{5-1}* y^{10-2})^{ \frac{3}{4} }=( \frac{16}{81 }* x^{4}* y^{8})^{ \frac{3}{4} }= \\  \\ = (\frac{16}{18} )^{ \frac{3}{4} }*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=
\frac{(16)^{ \frac{3}{4} }}{(18)^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} }=\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } \\  \\ &#10; (x^{a} )^{b} = x^{a*b}  \\  \\ &#10;\frac{( 2^{4} )^{ \frac{3}{4} }}{( 3^{4} )^{ \frac{3}{4} }}*(x^{4})^{ \frac{3}{4} }*(y^{8})^{ \frac{3}{4} } =  \frac{ 2^{4* \frac{3}{4} } }{ 3^{4* \frac{3}{4} } } * x^{4* \frac{3}{4} } * y^{8*\frac{3}{4}} = \frac{ 2^{3} }{ 3^{3} } * x^{3} *y^{6} = 
= \frac{8x^{3}y^{6}  }{27}

Q2. The answer is 1/16

(-64) ^ \frac{-2}{3} =(-1* 2^{6} ) ^ \frac{-2}{3}=(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} \\\\x^{-a} =  \frac{1}{ x^{a} } \\\\(-1)^ \frac{-2}{3} *(2^{6} ) ^ \frac{-2}{3} = \frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{(2^{6})^ \frac{2}{3}} \\  \\  (x^{a} )^{b}=x^{a*b} \\\\x^{ \frac{a}{b} = \sqrt[b]{ x^{a} } }  \\  \\ &#10;
\frac{1}{(-1)^ \frac{2}{3}} *\frac{1}{2^{6*\frac{2}{3}}} = \frac{1}{ \sqrt[3]{(-1)^{2} } } * \frac{1}{ 2^{4} } =  \frac{1}{ \sqrt[3]{1} } * \frac{1}{16} = \frac{1}{1} * \frac{1}{16}= \frac{1}{16}


Q3. The answer is a^{ \frac{7}{6} }

a^{ \frac{2}{3} } * a^{ \frac{1}{2} }  \\  \\ &#10; x^{a}* x^{b}  =x^{a+b}  \\  \\ &#10;a^{ \frac{2}{3} } * a^{ \frac{1}{2} }= a^{ \frac{2}{3} + \frac{1}{2} } =a^{ \frac{2*2}{3*2} + \frac{1*3}{2*3} }=a^{ \frac{4}{6} + \frac{3}{6} }=a^{ \frac{4+3}{6} }=a^{ \frac{7}{6} }
7 0
2 years ago
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Answer:

Step-by-step explanation:

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3 years ago
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