A. 80 students
B. 12 students
Slope for the function is -1/3.5.
I did get the one in the tux ♂️ and the other one ☝️
Y = cos(x)
sqrt(3)/2 = cos(30º)
dy = -sin(x)*dx
dy = -sin(30º)*(pi/180) = (1/2)*(pi/180)
y + dy = cos(x) - sin(x)dx
y + dy = sqrt(3)/2 - (1/2)*(pi/180) = 0.8573
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So the two possible original temperatures would be either -9 or 9.
