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monitta
3 years ago
13

A square has an unknown side length of x feet. It is transformed into a rectangle by increasing its length by 12 feet and decrea

sing its width by 4 feet.
(a) Determine a trinomial expression for the area of the new rectangle in terms of x. Create an area model to illustrate how you found your answer.

(b) If the area of the new rectangle is equal to the area of the original square, then find the numerical side length of the original square, x. Show how you found your answer.
Mathematics
1 answer:
MAXImum [283]3 years ago
6 0

Answer:

(a) Area = x^2 + 8x - 48

(b) x = 6

Step-by-step explanation:

Given

Let the side length of the square be x

So, the rectangle has:

Length = x + 12 -- increase by 12

Width = x - 4 --- decrease by 4

Solving (a): The area of the rectangle.

This is:

Area = Length * Width

Area = (x + 12) *(x - 4)

Open brackets

Area = x^2 + 12x - 4x - 48

Area = x^2 + 8x - 48

Solving (b): Find x

The area of the square is:

Area = x^2

If the rectangle has the same area, then:

x^2 + 8x - 48 = x^2

Collect like terms

8x - 48 = x^2 - x^2

8x - 48 = 0

8x = 48

Solve for x

x = 6

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Answer:

- The center of hyperbola is (-2 , 3)

- The left vertex, if the hyperbola opens horizontally, or the

  bottom vertex, if it opens vertically, is (-6 , 3)

- The other vertex is (2 , 3)

Step-by-step explanation:

* Lets study the equation of the hyperbola

- The standard form of the equation of a hyperbola with  

  center (h , k) and transverse axis parallel to the x-axis is

  (x - h)²/a² - (y - k)²/b² = 1, Where

- The length of the transverse axis is 2a

- The coordinates of the vertices are (h ± a , k)

- The length of the conjugate axis is 2b

- The coordinates of the co-vertices are (h , k ± b)

- The coordinates of the foci are (h ± c , k), where c² = a² + b²

* Now lets solve the problem

∵ (x + 2)²/4² - (y - 3)²/5² = 1

∵  (x - h)²/a² - (y - k)²/b² = 1

∴ a = 4 , b = 5

∴ h = -2 , k = 3

∵ The center of the hyperbola is (h , k)

∴ The center of hyperbola is (-2 , 3)

∵ The coordinates of the vertices are (h + a , k)  , (h - a , k)

∴ The coordinates of the vertices are (-2 + 4 , 3)  , (-2 - 4 , 3)

∴ The coordinates of the vertices are (2 , 3)  , (-6 , 3)

∴ The left vertex, if the hyperbola opens horizontally, or the

  bottom vertex, if it opens vertically, is (-6 , 3)

∴ The other vertex is (2 , 3)

6 0
4 years ago
Find the distance between the points (-4,0) and (2,1). If necessary,round to the nearest 10th.
Gelneren [198K]

Answer:

square root of 37

Step-by-step explanation:

you would use the formula (X2-X1) squared + (Y2-Y1) squared

8 0
3 years ago
Grace is comparing cell phone plans. A prepaid phone plan costs $0.20 per minute and has no monthly fee. A contracted phone plan
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Answer:

B

Step-by-step explanation:

The contracted phone plan will have the same steepness and a higher y-intercept.

4 0
3 years ago
Mr.Wells tells his class of 24 that when they have compleyed the assignment they may play online math games.At the end of class,
Tanzania [10]

Answer:

14

Step-by-step explanation:

Because 40% of the class is playing games, that means (100-40)% aren't playing, meaning that those 60% haven't finished the assignment.

We find 60% of the total 24 students, and that is .6 * 24 = 14.4

Because you can't have .4 people, the answer rounds (down ) to 14

5 0
4 years ago
Read 2 more answers
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Answer:

24 chairs in each class needed

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700 chairs total

how many extra chairs

chairs will be c

t is total

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opposite of multiplication is division( 25 is multiplying by c) c needs to be alone

25 classrooms times chairs equal total chairs

t is 700

700=25×c

700/25=25/25c

700/25=C

c is 28

so 28 chairs for 25 classrooms

they need 24 chairs per class

so there are 4 extra chairs per class

4×25 is 100

**or just multiply 25 classes and 24 chairs

25 times 24 is 600

there are 700 chairs

100 left over

so 100 extra chairs

4 0
3 years ago
Read 2 more answers
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