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Taya2010 [7]
3 years ago
15

Pleasseeeeeee hellpppppo

Mathematics
1 answer:
guajiro [1.7K]3 years ago
7 0
ITS C !!!!!!!!!!!!!!!!!!!!!
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Choose the symbol that compares the fractions.<br> 1/10 7/8
MatroZZZ [7]
1/10 < 7/8

Hope this helps :)
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3 years ago
Choose Yes or No to tell if each statement is true.
fgiga [73]

Answer:

No, no, yes, yes

Step-by-step explanation:

3.072 is not bigger than 3.2, so incorrect (no)

728.307 is not bigger than 729.078, so incorrect again (no)

12.040 does equal 12.04, so correct (yes)

531.135 is smaller than 531.315, so correct (yes)

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3 years ago
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At a​ little-known vacation​ spot, taxi fares are a bargain. A ​63-mile taxi ride takes 72 minutes and costs ​$50.40. You want t
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$26.60, take 72/50.40 to find how much money it is per minute. Set that equal to 38/x- x being the unit price you’re trying to find. Then cross multiply to get $26.60
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Divide x^6/(x^2+1) Please help quickly and thank you!
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3 0
3 years ago
There are 16 kids on a soccer team. The players are either boys or girls, and they either prefer playing offense or defense. The
Mariana [72]

Answer:

P(B|A)=\frac{2}{7}

Step-by-step explanation:

The probability of P(B|A) can be read as the probability of event B occurring given event A. In this question, event A occurs when the chosen player is a girl. There are 7 girls on the soccer team. Event B occurs when the chose player plays defense. Since P(B|A) stipulates that event A already occurred, we want the probability of choosing a player who prefers defense from the 7 girls. There are 2 girls who prefer defense, hence P(B|A)=\boxed{\frac{2}{7}}.

<u>Alternative:</u>

For dependent events A and B, the conditional probability of event B occurring given A is given by:

P(B|A)=P(B\cap A)\div P(A)

P(B\cap A) indicates the intersection of P(B) and P(A). In this case, it is the probability that both events occur. Since there are 16 kids on the soccer team and only 2 are girls and prefer defense, P(B\cap A)=\frac{2}{16}=\frac{1}{8}. The probability of event A occurring (chosen player is a girl) is equal to the number of girls (7) divided by the number of kids on the team (16), hence P(A)=\frac{7}{16}.

Therefore, the probability of event B occurring, given event A occurred, is equal to:

P(B|A)=\frac{1}{8}\div \frac{7}{16},\\\\P(B|A)=\frac{1}{8}\cdot \frac{16}{7}=\boxed{\frac{2}{7}}

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3 years ago
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