The other 2 angles of given right angles are 61.93° and 28.072°, if a triangle with side lengths 8, 15, and 17 is a right triangle by the converse of the Pythagorean Theorem.
Step-by-step explanation:
The given is,
Right angled triangle,
Side lengths are 8, 15, and 17
Step:1
The given triangle is right angle triangle by the converse of Pythagorean theorem, so the trigonometric ratio,
Ref the attachment,
For angle a,
...................................................(1)
Where, Opp - 8
Hyp - 17
From equation (1),
= 0.470588
(0.470588)
a = 28.072°
For angle b,
...................................................(1)
Where, Opp - 15
Hyp - 17
From equation (1),
= 0.882352
(0.882352)
b = 61.93°
Step:2
Check for solution for right angle triangle,
90 ° = Other 2 angles
90 ° = a + b
90 ° = 28.072° + 61.93°
90 ° = 90 °
Result:
The other 2 angles of given right angles are 61.93° and 28.07°, if a triangle with side lengths 8, 15, and 17 is a right triangle by the converse of the Pythagorean Theorem.
Step-by-step explanation:
the rhombus is both rectangle and square
Answer:
It will travel high enough
Step-by-step explanation:
Find the vertex of the parabola:
x=-b/2a
x=-11/2(-16)
x=-11/-32
x=11/32
Plug x=11/32 into quadratic to get the y-coordinate:
h=-16(11/32)^2+11(11/32)+5.5
h=7.391
Since 7.391>7.3, the volleyball will travel high enough (aka. yes)
Y = -6.
-2(7)-2y=-2
-14-2y=-2
you need to move -14 to the other side by canceling out -14 with +14, and add +14 to -2, giving you -2y=12. -2/12=-6
Answer:
5/V2=2.5×V2
Step-by-step explanation:
This is an isoscelle right triangle:
x²+x²=5²
2x²=5²
x=5/V2=5×V2/2=2.5×V2
where V2=sqrt(2)
