0.04035. that's it I think
<span>3 = log(8) + log(x³) </span>
<span>When adding logs, you are multiplying the terms altogether. </span>
<span>3 = log(8x³) </span>
<span>Then, by log_a b = n ==> aⁿ = b: </span>
<span>10³ = 8x³ [Since the base is not given, I assume that the base is 10] </span>
<span>1000 = 8x³ </span>
<span>Finally, solve for x. </span>
<span>1000/8 = x³ </span>
<span>x³ = 125 </span>
<span>x = (125)^(1/3) . . .Set both sides to the power of 1/3. </span>
<span>x = 5 </span>
<span>Hence, x = 5. </span>
Answer:
The answer is below
Step-by-step explanation:
a) Let negative means the turtle position when descending and positive for going up. Therefore since the turtle was 850 meters below see level, it was at -850. It then moves 165 meters up, hence its new position is -685 meters (-850 + 165). Lastly it moves down 165 meters, hence its new position is -850 meters (-685 - 165)
b) The change in position is the sum of the movements = +165 - 165 = 0 meters.
Answer:
The length of the call that would cost the same with both cards is 5 minutes.
Step-by-step explanation:
Hi there!
The cost with card A can be expressed as follows:
cost A = 30 + 2 · m
Where "m" is the length of the call in minutes.
In the same way, the cost of card B will be:
cost B = 10 + 6 · m
Where "m" is the length of the call in minutes.
We have to find the value of "m" for which the call would cost the same with both cards.
Then:
cost A = cost B
30 + 2 · m = 10 + 6 · m
Subtract 10 and 2 · m to both sides of the equation:
30 - 10 = 6 · m - 2 · m
20 = 4 · m
Divide by 4 both sides of the equation:
20/4 = m
5 = m
The length of the call that would cost the same with both cards is 5 minutes.
Have a nice day!
