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arlik [135]
3 years ago
13

Find the missing measure of the arc formed by the endpoints of a central angle.​

Mathematics
1 answer:
Alina [70]3 years ago
4 0

Answer:

The missing measure of the arc is 125°.

Step-by-step explanation:

Since the circle is 360°, you would first subtract 360 by the degrees given: 360-115-35-85 and the sum is 125. Then, you would set 125 equal to -32x-3 to solve for x.

125=-32x-3

+3               +3

-----------------------

\frac{128}{-32} =\frac{-32x}{-32}

x=-4

The missing measure of the arc is 125°.

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If the probability of being hospitalized during a year is 0.15 find the probability that no one in the family of 4 will be hospi
Goryan [66]

The probability that no one in the family of 4 will be hospitalized during a year is 0.52

Step-by-step explanation:

The probability for a person to be hospitalized during one year is

p(h)=0.15

As a consequence, the probability for a person of NOT being hospitalized during one year is

p(h^{-1})=1-0.15=0.85

If we have 4 people in the family, the probability of each of them of NOT being hospitalized during the year is independent from the probability of the others - therefore, these are independent events. This means that the total probability of the 4 people of not being hospitalized during a year is:

p(h^{-1})^4=(0.85)^4=0.52

So, the probability that no one in the family of 4 will be hospitalized during a year is 0.52.

Learn more about probability:

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#LearnwithBrainly

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3 years ago
What is the domain of the graphed function
azamat

Answer:

the third option. x is a real number

6 0
3 years ago
Which of the following phrases are expressions?
Hoochie [10]

Answer:

-6k = -8 is an expression

A and C are inequalities

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3 0
3 years ago
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It is known that IQ scores form a normal distribution with a mean of 100 and a standard deviation of 15. If a researcher obtains
sdas [7]

Answer:

X \sim N(100,15)  

Where \mu=100 and \sigma=15

We select a sample of n=16 and we are interested on the distribution of \bar X, since the distribution for X is normal then we can conclude that the distribution for \bar X is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Because by definition:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

E(\bar X) = \mu

Var(\bar X) = \frac{\sigma^2}{n}

And for this case we have this:

\mu_{\bar X}= \mu = 100

\sigma_{\bar X} = \frac{15}{\sqrt{16}}= 3.75

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:

X \sim N(100,15)  

Where \mu=100 and \sigma=15

We select a sample of n=16 and we are interested on the distribution of \bar X, since the distribution for X is normal then we can conclude that the distribution for \bar X is also normal and given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Because by definition:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

E(\bar X) = \mu

Var(\bar X) = \frac{\sigma^2}{n}

And for this case we have this:

\mu_{\bar X}= \mu = 100

\sigma_{\bar X} = \frac{15}{\sqrt{16}}= 3.75

6 0
3 years ago
If i have a 74.23% in math class and i get a 0 on a Summative Assignment, what is my new grade?
Talja [164]
Not good, at all man, you should really invest in a tutor.
5 0
4 years ago
Read 2 more answers
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