Answer:
Probability ball: white - P(W)P(W);
Probability ball: even - P(E)P(E);
Probability ball: white and even - P(W&E).
Probability ball picked being white or even: P(WorE)=P(W)+P(E)-P(W&E).
(1) The probability that the ball will both be white and have an even number painted on it is 0 --> P(W&E)=0 (no white ball with even number) --> P(WorE)=P(W)+P(E)−0P(WorE)=P(W)+P(E)−0. Not sufficient
(2) The probability that the ball will be white minus the probability that the ball will have an even number painted on it is 0.2 --> P(W)−P(E)=0.2P(W)−P(E)=0.2, multiple values are possible for P(W)P(W) and P(E)P(E) (0.6 and 0.4 OR 0.4 and 0.2). Can not determine P(WorE)P(WorE).
(1)+(2) P(W&E)=0 and P(W)−P(E)=0.2P(W)−P(E)=0.2 --> P(WorE)=2P(E)+0.2P(WorE)=2P(E)+0.2 --> multiple answers are possible, for instance: if P(E)=0.4P(E)=0.4 (10 even balls) then P(WorE)=1P(WorE)=1 BUT if P(E)=0.2P(E)=0.2 (5 even balls) then P(WorE)=0.6P(WorE)=0.6. Not sufficient.
Answer: E.
Answer:
A = x(x − 4) − 0.5(8)(x − 4) − 3(7)
Step-by-step explanation:
x = length, making the width (x-4)
The stage closet will be (x-4)(8)(1/2)
The rectangle is 7(3)
That makes the painted area x(x-4) - 4(x-4)
So...
A = x(x − 4) − 0.5(8)(x − 4) − 3(7)
Answer:
235.5 ft³
Step-by-step explanation:
V = Ab×h
= πr²×h
= π(2.5)²×12
= 3.14×6.25×12
= 235.5 ft³
The sum of 38 and twice a number x is 124. The value of "x" is 43
- 2x - 5 is equal to – 91.
<u>Solution:</u>
Given that , The sum of 38 and twice a number x is 124.
We have to find what is - 2x - 5?
Now, according to given information, 38 + 2 × x = 124
2x + 38 = 124
2x = 124 – 38
2x = 86
x = 43
So, the value of x is 43
<em><u>Now, Evaluating - 2x – 5 </u></em>
Substitute "x" = 43 to evaluate
- 2(43) – 5
- 86 – 5 = - 91
Hence, the required answer is – 91.
Answer:
Step-by-step explanation:
