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KengaRu [80]
3 years ago
10

Jess gave her nail technician a ​$4.80 tip. The tip was 16​% of the cost of the manicure. Write an equation to find​ b, the cost

of the manicure.

Mathematics
1 answer:
Arlecino [84]3 years ago
4 0

Answer: The equation is B = $4.80 / .16

Step-by-step explanation:

In order to calculate the cost of the purchase you must divide the amount of sales tax by the sales tax rate. The correct formula for this question is B = $4.80 / .16.

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10
<u>x5
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</u>Using the math above, we can see that Mary needs 50 square yards of carpet to cover the entire dining room floor.<u>
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7 0
3 years ago
Evaluate the integral Integral from 0 to 1 Integral from 0 to 3 Integral from 3 y to 9 StartFraction 6 cosine (x squared )Over 5
Natalka [10]

Answer:

\int^1_0\int^3_0\int^9_{3y}\frac{6 cos x^2}{5\sqrt z}dxdydz =\frac{18}{5}(1+\frac{sin2}{2})

Step-by-step explanation:

cosine x²= cos x²

Rule

  • \int x^ndx= \frac{x^{n+1}}{n+1}+c
  • \int cos \ mx \ dx = \frac{sin \ mx}{m}+c
  • \int \frac{1}{\sqrt x}dx = \frac{\sqrt x}{\frac{1}{2}}  +c= 2\sqrt x+c

Given that,

\int^1_0\int^3_0\int^9_{3y}\frac{6 cos x^2}{5\sqrt z}dxdydz

=\int ^1_0[\int^3_0(\int^9_{3y} \frac{6cos x^2}{5\sqrt z}dz)dy]dz

=\int^1_0[\int^3_0([\frac{6cos x^2 \times \sqrt z}{5\times \frac{1}{2}}]^9_{3y})dy]dx

=\int^1_0[\int^3_0([\frac{12cos x^2 \times( \sqrt 9-\sqrt{3y})}{5}])dy]dx

=\int^1_0[\int^3_0([\frac{12cos x^2 \times( 3-\sqrt{3y})}{5}])dy]dx

=\int^1_0[\frac{12cos x^2 \times( 3y-\frac{\sqrt{3}y^\frac{3}{2}}{\frac{3}{2}})}{5}]^3_0dx

=\int^1_0[\frac{12cos x^2 \times( 3.3-\frac{2\sqrt{3}.3^\frac{3}{2}}{3})}{5}]^3_0dx

=\int^1_0[\frac{12cos x^2 \times( 9-6)}{5}]dx

=\frac{18}{5}\int^1_02cos x^2dx

=\frac{18}{5}\int^1_0(1+cos2x)dx

=\frac{18}{5}[(x+\frac{sin2x}{2})]^1_0

=\frac{18}{5}(1+\frac{sin2}{2})

6 0
3 years ago
How do i simplify 2a 3(4a-5)?
____ [38]
2a 3x4a +3x-5
2a+12a-15
14a-15
i think thats the answer
8 0
3 years ago
What is the smallest prime number p such that
Ne4ueva [31]

The smallest prime number of p for which p^3 + 4p^2 + 4p has exactly 30 positive divisors is 43.

<h3>What is the smallest prime number of p for which p must have exactly 30 positive divisors?</h3>

The smallest number of p in the polynomial equation p^3 + 4p^2 + 4p for which p must have exactly 30 divisors can be determined by factoring the polynomial expression, then equating it to the value of 30.

i.e.

  • p^3 + 4p^2 + 4p

By factorization, we have:

  • = p(p+2)²

Now, to get exactly 30 divisor.

  • (p+2)² requires to give us 15 factors.

Therefore, we can have an equation p + 2 = p₁ × p₂²

where:

  • p₁ and  p₂ relate to different values of odd prime numbers.

So, for the least values of p + 2, Let us assume that:

  • p₁ = 5 and p₂ = 3

p + 2 = 5 × 3²

p + 2 = 5 × 9

p + 2 = 45

p = 45 - 2

p = 43

Therefore, we can conclude that the smallest prime number p such that

p^3 + 4p^2 + 4p has exactly 30 positive divisors is 43.

Learn more about prime numbers here:

brainly.com/question/145452

#SPJ1

8 0
2 years ago
Help me please, i really don't understand!!
Nat2105 [25]

Answer:

x plus 4 divided by 5 minus 9

x + 4 / 5 - 9

4 0
3 years ago
Read 2 more answers
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