Let the width of the rectangle be W in.
Therefore, length = 2W in
Area of the rectangle, Ar = L*W = 2W*W = 2W^2
Also, perimeter of the rectangle, Pr = 2(L+W) = 2(2W+W) = 2(3W) = 6W
Then, perimeter of square, Ps = 52-6W
And, area of the square, As = [(52-6W)/4]^2 = [13-1.5W]^2 = (13-1.5W)(13-1.5W) = 169-19.5W-19.5W+2.25W^2 = 2.25W^2-39W+169
Therefore,
Total area, At = Ar+As = 2W^2+2.25W^2-39W+169 = 4.25W^2 -39W+169
For maximum area, the first derivative of the total area expression should be zero. Therefore;
dAt/dW = 8.5W - 39 = 0 => 8.5W = 39 => W = 39/8.5 = 4.588 in
Therefore, for maximum area, width (W) should be 4.588 in
Answer:
(b) segment EG and segment OM
Step-by-step explanation:
SAS is short for side-angle-side. It refers to claiming congruence by demonstrating the sides on either side of a given angle are congruent to their counterparts.
You want to identify the sides that need to be congruent on the other side of the congruent angle.
Note that in triangle MON, sides OM and ON are either side of angle O.
In triangle GEF, sides EG and EF are on either side of angle E.
We already know angle O is congruent to angle E, and we know side EF is congruent to ON. The other sides of the angle need to be congruent for the triangles to be congruent by SAS:
EG ≅ OM . . . . . matches the 2nd choice
Answer:
130.26
Step-by-step explanation:
257.40-21.82-150.32=45=130.26
Answer:
None
Step-by-step explanation:
DONUTS CANNOT BECOME BROWNIES