The number of different three-digit numbers that can be set for the combination lock is 125
<h3>How to determine the number of different locks?</h3>
The digits are given as
Digit = 1, 2, 3, 4, 5
Each digit can be repeated on the number lock.
So, the individual digit of the lock can be any of the 5 digits.
So, we have:
Locks = 5 * 5 * 5
Evaluate
Locks = 125
Hence, the number of different three-digit numbers that can be set for the combination lock is 125
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The answer is B. 0.25 inch. Lets multiply all of them by the same factor. Since A. and B. have 3 decimals, lets divide all numbers by 1000: A. 0.026 * 1000 = 26, B. 0.25 * 1000 = 250, C. 0.24 * 1000 = 240, D. 0.025 * 1000 = 25. So, by comparing the whole numbers, it can be concluded that the biggest steel rod is B. 0.25 inch.
Hello from MrBillDoesMath!
Answer:
Choice C (6)
Discussion:
Since it is an isosceles trapezoid the length of the two legs (i.e. AB = 5y-10 and CD = 2y+8) are equal. In other words,
5y - 10 = 2 y + 8
Subtract 2y from each side:
5y - 2y - 10 = 8
Now add 10 to each side
5y - 2y - 10 + 10 = 8 + 10 =>
3y + 0 = 18 =>
3y = 18 =>
y = 6
Regards,
MrB
Step-by-step explanation:
9x - 2 = 5x + 54 because these angles are corresponding
9x - 5x = 54 + 2 add/subtract like terms
4x = 56 and this divided by 4
x = 14
9x - 2 + 10y + 6 = 180° because these two angles makes a straight line
9×14 - 2 + 10y + 6 = 180°
126 - 2 + 10y + 6 = 180° add like terms
130 + 10y = 180° subtract 130 from both sides
10y = 50 divide by 10
y = 10
