Answer:
The answer is insulin.
Explanation:
Pancreatic juice is an enzyme containing secretion produced by the pancreas into the small intestine. Enzymes in the pancreas help in digesting proteins, carbohydrates and fats. The constituent enzymes are as follows:
- Trypsinogen and Chymotrypsinogen: Precursors of the proteases, trypsin and chymotrypsin that digest proteins. They are released as precursors to protect the intestinal lining. Enterokinase, an enzyme secreted by small intestine's epithelial cells, activates these precursor.
- Lipase: Enzyme that digests lipids by hydrolysing triglycerides into 2-monoglyceride and two free fatty acids.
- Amylase that helps in digesting any left over carbohydrates and complex starch.
Insulin:
Insulin can never be part of pancreatic juice because it is a hormone, not an enzyme. Hormones are chemical messengers secreted only in blood. Insulin is a hormone secreted by the pancreas to lower blood glucose levels by binding to insulin receptors on cells and stimulating the intake of glucose through glucose transport channels (GLUTs) in the cell membrane.
The two organs have different adrenergic receptors for NE.
Answer:
The atomic number of phosphorus is 15. It has zero charge because it has 15 electrons.
<span>Cohesion- attraction of molecules of the same substanceCauses water molecules to be drawn together to form a smooth surface (surface tension)adhesion- attraction of molecules to different substances<span>The correct answer is A because the cohesion causes water to form in drops, and adhesion allows it to stick to different substances, such as the pine needles</span></span>
Answer:
Null Hypothesis -
The observed frequency is approximately equal to the expected frequency of phenotype.
Explanation:
Pure Breeding Cross - TTww x ttWW
Genotype of offspring in F2 generation - TtWw
Null Hypothesis -
The observed frequency is approximately equal to the expected frequency of phenotype.
The chi square analysis is attached
The degree of freedom for this question is 3
The p value for X^2 estimated through chi square test is 0.5
Hence the null hypothesis is accepted.
