List the 3 components of the hand

Biology

1 answer:

coldgirl [10]4 years ago

4 0

Carpet, meta carpel and phalanges

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When did hans and zacharias janssen contribute to the cell theory

Luda [366]

1595 Zachariah’s Jansen was a Dutch spectacle maker from middleburg son to hand Jansen .

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3 years ago

In Drosophila, a very prolific phenotypically normal female was crossed to a phenotypically normal male. All of the female offsp

erastova [34]

Answer:

22 mu

Explanation:

Since maximum number of flies are observed with +pb and s++ phenotype, they are the parental combinations.

Minimum number of flies are observed with +p+ and s+b phenotype hence they are the result of double crossover.

Gene order would be +bp and s++ since it is the only case which would lead to production of above mentioned double crossover. Hence gene b is in the middle of genes s and p.

Single cross over between genes s and b will give progeny +++ and sbp.

Map distance between s and b loci = recombination frequency =

(number of recombinants/ total progeny)*100

= [(single cross over between s and b + double crossover)/total progeny]*100

= [(102+106+7+5/1000]*100

=(220/1000)*100

=0.22*100

=22 mu

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4 years ago

In rabbits, black fur (B) is dominant to white fur (b). A purebred black furred male is bred with a female that had the recessiv

ValentinkaMS [17]

Answer:

All the offsprings will be black-furred (Bb)

Explanation:

This question involves a single gene coding for fur length in rabbits. The allele for black fur (B) is dominant to the allele for white fur (b). This means that a rabbit heterozygous for this gene (Bb) will have a black fur.

According to this question, a purebred black furred male (BB) is bred with a female that had the recessive white fur (bb). The parents will produce gametes as follows:

BB - B only

bb - b only

Using these gametes in a punnet square (see attached image), the genotypic proportion of the produced offsprings is as follows:

Bb, Bb, Bb, Bb

All Bb (heterozygous) means that all of the offsprings will be black-furred.