Please help ASAP!!!!
1 answer:
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Answer:
84°
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached photo.
Given that:
- ∠LOI=38°
- ∠JOP=84 °
As we can see from the figure that ∠JOP and ∠JKP are on the same segment JP. Hence, ∠JOP and ∠JKP are congruent and the angle of ∠JKP is 84°
$=(a^2-10a)-(b^2+6b) +16$
$=[(a^2-2(5)a+25)-25]-[(b^2+2(3)b+9)-9]+16$
$=(a-5)^2-25-(b+3)^2+9+16$
$=(a-5)^2-(b+3)^2$