A large rectangle has side lengths of 8 meters and 6 meters. This means that the area of the large rectangle will be:
= 8m × 6m
= 48m²
A smaller rectangle with side lengths of 4 meters and 2 meters is cut out of the large rectangle. Then, the area of the smaller rectangle will be:
= 4m × 2m
= 8m²
Since the smaller rectangle with side lengths of 4 meters and 2 meters is cut out of the large rectangle whose length is 8, meters and 6 meters, the remaining part of the rectangle will have length of (8m - 4m) = 4m and (6m - 2m) = 4m.
Area of the remaining part of the large rectangle will be:
Answer: x = -1 y = 4 I got my answer by solving for one variable in the first equation and then substituting what I got for that variable into the second equation in place of that aforementioned variable then solving for the last variable.
