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3 years ago

You jog 2 miles every 15 minutes.How much do you jog per minute?Write you answer as a fraction in simplest form.

2 answers:

6 0

You divide 2 by 15, you get 0.1333 (the three goes on and on) then you conver it into a fraction, its 2/15. Hope this helps :)

Lostsunrise [7]3 years ago

4 0

This is a simple question, you just divide 2 by 15 which equals about 13/100

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2.) Bill sells cleaning products on commission. He earns 40% commission on his sales. If

valentina_108 [34]

Answer:

Step-by-step explanation:

what you have to do if figure out what forty percent is if you know what fifty is then u know that 40 is half minus ten so start buy dividing that by 2 then subtract ten and there's your answer

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3 years ago

Twice as large as the sum of 11 and 7

Nutka1998 [239]

I think the answer is 34

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3 years ago

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Graph the linear equation 2x-2y=8

Margaret [11]

equation: y = x - 4

y-intercept = -4

gradient/slope = 1/1x or x

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John borrowed $1200 from his credit union at 18% simple interest. He agrees to repay the loan by making

kakasveta [241]

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3 years ago

A biologist is studying the growth of a particular species of algae. She writes the fall inclusion to show the radius of the alg

horrorfan [7]

Answer:

Part A)

A reasonable domain to plot the growth function is:

$0\leq d \leq 12$

Part B)

The y-intercept represents that when the biologist started her study, the radius of the algae was five millimeters.

Part C)

The average rate of change from d = 4 to d = 11 was about 0.11. This means that from the 4th day to the 11th, the radius of the algae grew, on average, at a rate of 0.11 mm per day.

Step-by-step explanation:

The radius of the algae f(d) in millimeters after d days is given by the function:

$f(d)=5(1.02)^d$

Part A)

We know that the radius of the algae was approximately 6.34 mm when the biologist concluded her study. To find the reasonable domain, we can substitute 6.34 for f(d) and solve for d. Therefore:

$6.34=5(1.02)^d$

Divide both sides by five:

$(1.02)^d=1.268$

Take the log of both sides with base 1.02:

$\displaystyle d=\log_{1.02}1.268$

Using the Change of Base Property, evaluate for d:

$\displaystyle d=\frac{\log 1.268}{\log 1.02}=11.9903...\approx 12$

So, the biologist concluded her study after 12 days.

Therefore, a reasonable domain to plot the growth function is:

$0\leq d\leq 12$

Part 2)

The y-intercept of the function is when d = 0. Find the y-intercept:

$f(0)=5(1.02)^{(0)}=5(1)=5$

Since d represent the amount of days after the study had begun, the y-intercept represents the radius of the algae on the initial day.

So, when the biologist started her study, the radius of the algae was five millimeters.

Part 3)

To find the average rate of change for a nonlinear function, we find the slope between the two endpoints on the interval.

We want to find the average rate of change of f(d) from d = 4 to d = 11.

Find the endpoints:

$f(4)=5.4121...\text{ and } f(11)=6.2168...$

And find the slope between them:

$\displaystyle m=\frac{f(11)-f(4)}{11-4}=0.1149...\approx 0.11$

Since f(d) measures millimeters and d measures days, this tells us that, on average, the radius of the algae grew by about 0.11 mm per day from the 4th day to the 11th day.

5 0

3 years ago