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balu736 [363]
3 years ago
8

Can someone help me with this please ?

Mathematics
1 answer:
Natali5045456 [20]3 years ago
6 0

Answer:

87 is the anwser

Step-by-step explanation:

Can i have brainlyest pls

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Please help i am so confused
harkovskaia [24]

Answer:

q\geq -81

Step-by-step explanation:

First, begin by multiplying \frac{q}{27} \\ by its reciprocal.

To do this, flip the fraction upside-down.

The resulting equation looks like this: \frac{27}{1} *\frac{q}{27}

Cancel out the two 27's and you are left with \frac{q}{1} , which you can simplify to q.

Next, multiply -3 by \frac{27}{1} . Remember, what you do on one side, you must do on the other.

Your equation should look like this:

q\geq -81

The final answer is q\geq -81 .

Have a nice day!

3 0
3 years ago
A train is traveling at the rate of 135 miles per hour. How far will the train travel in 3 hours?
dedylja [7]

Answer:

d.405

Step-by-step explanation:

135 x3=405

4 0
3 years ago
HELP I need to fine the slope-intercept form. Please it’s a timed assignment I only have two try’s and I already used one
barxatty [35]

Answer:

5. y = -1/2x + 6

6.  y = 1/2x + 150

7. y = 10x + 20

8. y = 25x

Step-by-step explanation:

Look at the y-intercept and eliminate the answers you dont need.

Then find the slope of each.

8 0
3 years ago
Help!!! ASAP!!!!!!!!
Svet_ta [14]

Answer:

-18y = 1

y = -1/18

5x - 9(-1/18)= -2

5x + 1/2 = -4/2

5x = -5/2

x = - 25/2

6 0
4 years ago
PLEASE PLEASE ANSWER!
muminat

The area of the shaded region is $8(\pi \ -\sqrt{3})\ \text{cm}^2.

Solution:

Given radius = 4 cm

Diameter = 2 × 4 = 8 cm

Let us first find the area of the semi-circle.

Area of the semi-circle = \frac{1}{2}\times \pi r^2

                                      $=\frac{1}{2}\times \pi\times 4^2

                                      $=\frac{1}{2}\times \pi\times 16

Area of the semi-circle = $8\pi cm²

Angle in a semi-circle is always 90º.

∠C = 90°

So, ABC is a right angled triangle.

Using Pythagoras theorem, we can find base of the triangle.

AC^2+BC^2=AB^2

AC^2+4^2=8^2

AC^2=64-16

AC^2=48

AC=4\sqrt{3} cm

Base of the triangle ABC = 4\sqrt{3} cm

Height of the triangle = 4 cm

Area of the triangle ABC = \frac{1}{2}\times b \times h

                                          $=\frac{1}{2}\times 4\sqrt{3}  \times 4

Area of the triangle ABC =  8\sqrt{3} cm²

Area of the shaded region

                   = Area of the semi-circle – Area of the triangle ABC

                   = $8\pi \ \text{cm}^2-8\sqrt{3}\ \text{cm}^2

                   = $8(\pi \ -\sqrt{3})\ \text{cm}^2

Hence the area of the shaded region is $8(\pi \ -\sqrt{3})\ \text{cm}^2.

3 0
3 years ago
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