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Mumz [18]
3 years ago
8

Mr. Jameson is walking toward his nine-story hotel and stops to look up to the top of the building. The angle of elevation to th

e top of the hotel is 55°. If the height of the hotel is 108 feet, about how far away is Mr. Jameson from the hotel?
Mathematics
1 answer:
tankabanditka [31]3 years ago
6 0
The side of the hotel is opposite to the angle.
The distance between Mr.Jameson and the hotel is adjacent to the measured angle.

Tan = sin/cos = adjacent/ opposite
Tan(55) = 108/x
x = 75.6ft

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