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hjlf
3 years ago
10

In the equation below, t is the time in hours it toon to drive to the beach. 63t=315

Mathematics
1 answer:
Tju [1.3M]3 years ago
6 0

Answer:

5 hours

Step-by-step explanation:

63t=315

t = 315/63

t=5

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What is the simplest fraction of 33%
cupoosta [38]
There is no simplest fraction, because no same numbers go into 33 and 100. (The hundred is from 33/100, because 33% and 33/100 are the same thing.
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3 years ago
Two manufacturing teams are producing light bulbs. The tables show their production over 5 days. Team Red Production Team Blue P
prisoha [69]

Answer:

Team Blue

Step-by-step explanation:

The reason this is, is because for each day that passes, they make 5 more light bulbs. This is in relation to the days that pass.

4 0
3 years ago
Which of the following has a graph that is a stight line?
Y_Kistochka [10]
Equation 1- does a u up so that is not stight  
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6 0
3 years ago
A scientist inoculates​ mice, one at a​ time, with a disease germ until he finds 3 that have contracted the disease. If the prob
UkoKoshka [18]

Answer:

The probability that 8 mice are​ required is 0.2428.

Step-by-step explanation:

Given : A scientist inoculates​ mice, one at a​ time, with a disease germ until he finds 3 that have contracted the disease. If the probability of contracting the disease is two sevenths.

To find : What is the probability that 8 mice are​ required? The probability that that 8 mice are required is nothing ?

Solution :

Applying binomial distribution,

P(X=r)=^nC_r p^rq^{n-r}

Where, p is the probability of success p=\frac{2}{7}

q is the probability of failure q=1-p, q=1-\frac{2}{7}=\frac{5}{7}

n is total number of trials n=8

r=3

Substitute the values,

P(X=3)=^8C_3 (\frac{2}{7})^3 (\frac{5}{7})^{8-3}

P(X=3)=\frac{8!}{3!5!}\times \frac{8}{343}\times (\frac{5}{7})^{5}

P(X=3)=\frac{8\times 7\times 6}{3\times 2\times 1}\times \frac{8}{343}\times \frac{3125}{16807}

P(X=3)=0.2428

Therefore, the probability that 8 mice are​ required is 0.2428.

5 0
3 years ago
What is the volume a circular spray tank if it has a diameter of 5 feet and height of 7 feet
Sedbober [7]
V=hpir^2
d/2=r
5/2/2.5

h=7
V=7pi2.5^2
v=7pi6.25
V=43.75pi
aprox pi=3.141592
V=137.44465


V=43.75pi ft^3 or aprox 137.44465 ft^3

7 0
3 years ago
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