Answers:
Part A: 12y² + 10y – 21
Part B: 4y³ + 6y² + 6y – 5
Part C: See below.
Explanations:
Part A:
For this part, you add Sides 1, 2 and 3 together by combining like terms:
Side 1 = 3y² + 2y – 6
Side 2 = 4y² + 3y – 7
Side 3 = 5y² + 5y – 8
3y² + 2y – 6 + 4y² + 3y – 7 + 5y² + 5y – 8
Combine like terms:
3y² + 4y² + 5y² + 2y + 3y + 5y – 6 – 7 – 8
12y² + 10y – 21
Part B:
You have the total perimeter and the sum of three of the sides, so you just need that fourth side value, which we can call d.
P = 4y³ + 18y² + 16y – 26
Sides 1, 2 & 3 = 12y² + 10y – 21
Create an algebraic expression:
12y² + 10y – 21 + d = 4y³ + 18y² + 16y – 26
Solve for d:
12y² + 10y – 21 + d = 4y³ + 18y² + 16y – 26
– 12y² – 12y²
10y – 21 + d = 4y³ + 6y² + 16y – 26
– 10y – 10y
– 21 + d = 4y³ + 6y² + 6y – 26
+ 21 + 21
d = 4y³ + 6y² + 6y – 5
Part C:
If closed means that the degree that these polynomials are at stay that way, then yes, this is true in these cases because you will notice that each side had a y², y and no coefficient value except for the fourth one. This didn't change, because you only add and subtract like terms.
Solution :
Given :
Sample mean, ![$\overline X = 34.2$](https://tex.z-dn.net/?f=%24%5Coverline%20X%20%3D%2034.2%24)
Sample size, n = 129
Sample standard deviation, s = 8.2
a. Since the population standard deviation is unknown, therefore, we use the t-distribution.
b. Now for 95% confidence level,
α = 0.05, α/2 = 0.025
From the t tables, T.INV.2T(α, degree of freedom), we find the t value as
t =T.INV.2T(0.05, 128) = 2.34
Taking the positive value of t, we get
Confidence interval is ,
![$\overline X \pm t \times \frac{s}{\sqrt n}$](https://tex.z-dn.net/?f=%24%5Coverline%20X%20%5Cpm%20t%20%5Ctimes%20%5Cfrac%7Bs%7D%7B%5Csqrt%20n%7D%24)
![$34.2 \pm 2.34 \times \frac{8.2}{\sqrt {129}}$](https://tex.z-dn.net/?f=%2434.2%20%5Cpm%202.34%20%5Ctimes%20%5Cfrac%7B8.2%7D%7B%5Csqrt%20%7B129%7D%7D%24)
(32.52, 35.8)
95% confidence interval is (32.52, 35.8)
So with
confidence of the population of the mean number of the pounds per person per week is between 32.52 pounds and 35.8 pounds.
c. About
of confidence intervals which contains the true population of mean number of the pounds of the trash that is generated per person per week and about
that doe not contain the true population of mean number of the pounds of trashes generated by per person per week.
Answer:
Inspite of giving special consideration to a particular employee, Jack consults everyone before taking any decision regarding the changes in the company's policy.
Answer:
4:5
Step-by-step explanation:
If there are 12 boys and 15 girls, the ratio of boys to girls will be 12:15.
However, this can be simplified by dividing each number by 3. This can be done since both 12 and 15 are divisible by 3.
12:15
= 4:5
So, the ratio of boys to girls in Timara's class is 4:5
Im so sorry but i am not into that:(