What is the solution of the system? {5x−y=−21x+y=−3 Enter your answer in the boxes. ( , )

Mathematics

1 answer:

Firdavs [7]3 years ago

3 0

Answer:

(-4,1)

Step-by-step explanation:

im pretty sure that is the answer, i will finish the test and tell you if it is right in the comments i guess lol

You might be interested in

Is y=3x+4 a function?

Oxana [17]

Answer:

Yes, it is a function

Step-by-step explanation:

Every possible input x value is paired with a unique output y value.

Another approach is to graph the function then conduct the VLT (vertical line test) at which point you will realize that any vertical line will intersect the graph at one point only meaning it is a function.

Hope this helps.

5 0

1 year ago

Ron tosses a 6-sided number cube labeled 1 to 6. Describe the probability that he tosses a number greater than 1. Explain your r

Brrunno [24]

5:6. cuz there are 5 numbers greater than 1 that can be rolled

4 0

3 years ago

Read 2 more answers

Let φ(x, y) = arctan (y/x) .

Alexandra [31]

Answer:

a) $\large F(x,y)=(-\frac{y}{x^2+y^2},\frac{x}{x^2+y^2})$

b) $\large \mathbb{R}^2-\{(0,0)\}$

c) the points of the form (x, -x) for x≠0

Step-by-step explanation:

If φ(x, y) = arctan (y/x), the vector field F = ∇φ would be

$\large F(x,y)=(\frac{\partial \phi}{\partial x},\frac{\partial \phi}{\partial y})$

On one hand we have,

$\large \frac{\partial \phi}{\partial x}=\frac{\partial arctan(y/x)}{\partial x}=\frac{-y/x^2}{1+(y/x)^2}=-\frac{y/x^2}{1+y^2/x^2}=\\\\=-\frac{y/x^2}{(x^2+y^2)/x^2}=-\frac{y}{x^2+y^2}$

On the other hand,

$\large \frac{\partial \phi}{\partial y}=\frac{\partial arctan(y/x)}{\partial y}=\frac{1/x}{1+(y/x)^2}=\frac{1/x}{1+y^2/x^2}=\\\\=\frac{1/x}{(x^2+y^2)/x^2}=\frac{x}{x^2+y^2}$