It gets mirrored or flipped
Answer:
The total number of combinations is 2,358,720,000
Step-by-step explanation:
For the letter part of the ID we have 3 letters out of a space of 26 possible letters (a-z), and they can't repeat. For the number part we want to group 5 numbers out of 10 possible algarisms (0-9).So we can make an arrangement for the letters and one for the numbers and multiply them. The arrangment can be done using the following formula:
A(n,k) = (n!)/(n-k)!
Where n is the total number of possibilities and k is the size of the group.
For the letters:
A(26,3) = (26!)/(26-3)! = (26!)/(23!) = (26*25*24*23!)/(23!) = 26*25*24 = 15600
For the numbers:
A(10,5) = (10!)/(10 - 5)! = 10!/5! = (10*9*8*7*6*5!)/(5!) = 10*9*8*7*6*5 = 151200
The total number of combinations is the product of both, so:
combinations = 15600*151200 = 2,358,720,000
Answer:
9+5=|2x+3|
14=|2x+3|
2 scenarios:
(1) 2x+3 >=0, equation is now 14=2x+3
11=2x
x=5.5
(2) 2x+3<0, equation is now 14=-(2x+3)
2x+3+14=0
2x=-17
x=-8.5
Step-by-step explanation:
Answer:
Min is 51 and max is 75 and the the mediem is 63 and the q1 is 54 and q2 is 55 and 57 and q3 is 65 and 69
Step-by-step explanation:
the least is 51 and the most is 75 and the mean is 63 if u list them in order and than u find the quartiles that are between the median and 51 and q3 is between the median and the max.