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tatiyna
3 years ago
5

What is 1 and 1/4 minus 3/8?

Mathematics
1 answer:
matrenka [14]3 years ago
6 0

Answer: 7/8

Step-by-step explanation:

You can change all the fractions to have equivalent denominators.

The Least Common Denominator of 1 1/4 and 3/8 is 8. Now we can change the fractions.

1 1/4 = 1 2/8 = 10/8.

3/8 = 3/8.

Now we can subtract. Subtract the numerators of the first fraction from the numerators of the second fraction, and the denominators oft he first fraction to the denominators of the second fraction.

10/8 - 3/8 = 7/8.

Therefore, 1 1/4 - 3/8 = 7/8; the fourth answer.

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One quarter has a mass of 5.67 grams. Which is the mass of two rolls of quarters each containing 40 quarters? how much is it?
Orlov [11]

Answer:

453.6 grams

Step-by-step explanation:

40 x 5.67 = 226.8

226.8 x 2 = 453.6

8 0
3 years ago
Read 2 more answers
Runner A is initially 6.0 km west of a flagpole and is running with a constant velocity of 3.0 km/h due east. Runner B is initia
ArbitrLikvidat [17]

Answer:

The distance of the two runners from the flagpole is 0.0882 km

Step-by-step explanation:

We are going to use the minus sign when the runner is on the west and the plus sign when the runner is on the east.

Then, Taking into account  the runner A is 6 km west and is running with a constant velocity of 3 Km/h east, the distance of the runner A from the flagpole is given by the following equation:

Xa = -6 Km + (3 Km/h)* t

Where Xa is the position of the runner A from the flagpole and t is the time in hours.

At the same way the distance of the runner B, Xb, from the flagpole is given by the following equation:

Xb = 7.4 Km - (3.8 Km/h)*t

Then, the two runners cross their path when Xa is equal to Xb, so if we solve this equation for t, we get:

              Xa = Xb

     -6 + (3*t) =  7.4 - (3.8*t)

(3.8*t) + (3*t) = 7.4 + 6

         (6.8*t) = 13.4

                  t = 13.4/6.8

                  t = 1.9706

Therefore, at time t equal to 1.9706 hours, both runners cross their path. The distance of the two runners from the flagpole can be calculated replacing the value of t in equation for Xa or in equation for Xb as:

Xa = -6 Km + (3 Km/h)* t

Xa = -6 Km + (3 Km/h)*(1.9706 h)

Xa = -0.0882 Km

That means that both runners are 0.0882 Km west of a flagpole.

4 0
3 years ago
Help would be very helpful :) the answers are: (812pi cm^3) (602pi cm^3) (735 cm^3) and (512pi cm^3) 30 points!!!!!
g100num [7]

Find the area of the top ( circle) then multiply by the height.

Area = pi x r^2

Area = pi x 7^2

Area = 49pi

Volume = 49pi x 15

Volume = 735pi cubic cm.

6 0
3 years ago
F(a) =-3a + 3; Find f(10)
Slav-nsk [51]

Answer:

-27

Step-by-step explanation:

f(a) = -3a + 3

f(10) = -3(10) + 3

= -30 + 3

= -27

3 0
3 years ago
What are the solutions to the equation 0 = x2 – x – 6? Check all that apply.
Mashcka [7]
X^2 - 3x + 2x - 6 = 0;
x( x - 3 ) + 2( x - 3 ) = 0;
( x - 3 )( x + 2 ) = 0;
x - 3 = 0 or x + 2 = 0;
x = 3 or x = 2
The solution to the equation are 2 and 3.
8 0
3 years ago
Read 2 more answers
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