05/23727.90=100/x
105x=23727.90x100
105x=2372790
(105x)/105=2372790/105
x=22598
dealers cost is $22,598
<span>the 105% is the 100% price of the car plus the 5% of that tax</span>
Answer:
The mean weight of the cats is 11.42 (rounded)
Step-by-step explanation:
To find the mean, you add up all the weights (12, 12, 9, 9, 11, 11, 16) and then divided the sum (80) of the weights by the number of cats (7)
12+12+9+9+11+11+16= 80
80 ÷ 7= 11.42857143 (I rounded my answer to 11.42)
I hope this was helpful. Have a wonderfull rest of your day!
Answer:
C
Step-by-step explanation:
Answer:
a) 30 kangaroos in 2030
b) decreasing 8% per year
c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo
Step-by-step explanation:
We assume your equation is supposed to be ...
P(t) = 76(0.92^t)
__
a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30
In the year 2030, the population of kangaroos in the province is modeled to be 30.
__
b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.
The population is decreasing by 8% each year.
__
c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.
P(100) = 75(0.92^100) = 76(0.0002392)
P(100) ≈ 0.0182, about 1/55th of a kangaroo
Answer:
The answer is the first option; 6^1/12
Step-by-step explanation:
We can simplify the question by using the radical rule to rewrite it as
6^1/3 ÷ 6^1/4
Then we use exponent rule which states that when we are dividing exponents of the same base, we have to subtract them. We see that the exponents are 1/3 and 1/4. So we use basic fractional division, here's the subtraction:
= 1/3 - 1/4
= 4/3 - 3/4 (we criss-crossed)
= 1/12 (we subtracted the denominators and multiplied the denominators)
Now that we have subtracted the exponents, we can write the answer as 6^1/12
