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gogolik [260]
3 years ago
7

A picture frame measures 5 inches wide and 7 inches long. What is the perimeter of the frame?

Mathematics
2 answers:
marin [14]3 years ago
7 0
The perimeter is 24.
Remember finding perimeter is always adding, so add 5 two times for the sides do the shape, do the same for 7, then you get your answer. Hope this helps!
Citrus2011 [14]3 years ago
3 0
The answer would be 24, 5+5+7+7=24
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In 1979, there were 2.4 million licensed registered nurses in a country. This number increased to 3.6 million in 2012. What is t
Dennis_Churaev [7]

Answer:

It is a 50% increase

Step-by-step explanation:

2.4 million /2 = 1.2 million

2.4m + 1.2m = 3.6m

50% of 2.4 is 1.2

it is a +50% increase to get from 2.4 to 3.6

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3 years ago
Give the degree of each polynomial
Norma-Jean [14]

Answer

Sorry! number 12 is 2

Step-by-step explanation:

8 0
3 years ago
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38. What is the surface area of a conical grain storage tank that has a height of 62 meters and a diameter of 24 meters? Round t
svetoff [14.1K]
1. The surface area of a cone S is S= \pi  r^{2}+  \pi rl, where r is the radius of the base and l is the slant height.

2. The slant height l is found as follows:

l^{2}= OC^{2}+ OB^{2}
l^{2}= 12^{2}+ 62^{2}=144+3844=3988

l= \sqrt{3988}=63.15

3. 

A=\pi r^{2}+ \pi rl=3.14(12)^{2}+3.14*12*63.15

= 452.16+2379.492 =2831.652 ( m^{2} )

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4. The answer is C

8 0
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What is -9/2+5/12 dhdjjxjxjxjxjxjjx
Scrat [10]

Answer:

-4 1/12.

Step-by-step explanation:

-9/2 + 5 /12

The Lowest Common denominator is 12 so we have:

-54/12 + 5/12

= -49/12

=  -4 1/12.

7 0
3 years ago
Determine the truth value of each of these statements if thedomainofeachvariableconsistsofallrealnumbers.
hoa [83]

Answer:

a)TRUE

b)FALSE

c)TRUE

d)FALSE

e)TRUE

f)TRUE

g)TRUE

h)FALSE

i)FALSE

j)TRUE

Step-by-step explanation:

a) For every x there is y such that  x^2=y:

 TRUE

This statement is true, because for every real number there is a square         number of that number, and that square number is also a real number. For example, if we take 6.5, there is a square of that number and it equals 39.0625.

b) For every x there is y such that  x=y^2:

 FALSE

For example, if x = -1, there is no such real number so that its square equals -1.

c) There is x for every y such that xy = 0

 TRUE

If we put x = 0, then for every y it will be xy=0*y=0

d)There are x and y such that x+y\neq y+x

 FALSE

There are no such numbers. If we rewrite the equation we obtain an incorrect statement:

                                   x+y \neq y+x\\x+y - y-y\neq 0\\0\neq 0

e)For every x, if   x \neq 0  there is y such that xy=1:

 TRUE

The statement is true. If we have a number x, then multiplying x with 1/x (Since x is not equal to 0 we can do this for ever real number) gives 1 as a result.

f)There is x for every y such that if y\neq 0 then xy=1.

TRUE

The statement is equivalent to the statement in e)

g)For every x there is y such that x+y = 1

TRUE

The statement says that for every real number x there is a real number y such that x+y = 1, i.e. y = 1-x

So, the statement says that for every real umber there is a real number that is equal to 1-that number

h) There are x and y such that

                                  x+2y = 2\\2x+4y = 5

We have to solve this system of equations.

From the first equation it yields x=2-2y and inserting that into the second equation we have:

                                   2(2-2y)+4y=5\\4-4y+4y=5\\4=5

Which is obviously false statement, so there are no such x and y that satisfy the equations.

FALSE

i)For every x there is y such that

                                     x+y=2\\2x-y=1

We have to solve this system of equations.

From the first equation it yields x=2-y  and inserting that into the second equation we obtain:

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Inserting that back to the first equation we obtain

                                            x=2-1\\x=1

So, there is an unique solution to this equations:

x=1 and y=1

The statement is FALSE, because only for x=1 (and not for every x) exists y (y=1) such that

                                         x+y=2\\2x-y=1

j)For every x and y there is a z such that

                                      z=\frac{x+y}{2}

TRUE

The statament is true for all real numbers, we can always find such z. z is a number that is halway from x and from y.

5 0
3 years ago
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