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joja [24]
3 years ago
5

(04.03) The graph shows the amount of money paid when purchasing bags of candy at the zoo: Total cost a Bags of Candy Write an e

quation to represent the relationship between the total cost (y) and the number of bags of candy (x).
A: y= 1 over 2 x
B: y= 2x
C: y=3x
D: y = 1 over 3 x​

Mathematics
1 answer:
Taya2010 [7]3 years ago
5 0

Answer:

B

Step-by-step explanation:

Slope of the line

(y2 - y1)/(x2 - x1)

(4-2)/(2-1)

2/1 =2

y = 2x

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Sliva [168]

Step-by-step explanation:

(n-m) out of n

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2 years ago
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25% of American households have only dogs (one or more dogs) 15% of American households have only cats (one or more cats) 10% of
sergeinik [125]

Answer:

a) P=0.2503

b) P=0.2759

c) P=0.3874

d) P=0.2051

Step-by-step explanation:

We have this information:

25% of American households have only dogs (one or more dogs)

15% of American households have only cats (one or more cats)

10% of American households have dogs and cats (one or more of each)

50% of American households do not have any dogs or cats.

The sample is n=10

a) Probability that exactly 3 have only dogs (p=0.25)

P(x=3)=\binom{10}{3}0.25^30.75^7=120*0.01563*0.13348=0.25028

b) Probability that exactly 2 has only cats (p=0.15)

P(x=2)=\binom{10}{2}0.15^20.85^8=45*0.0225*0.27249=0.2759

c) Probability that exactly 1 has cats and dogs (p=0.1)

P(x=1)=\binom{10}{1}0.10^10.90^0=10*0.1*0.38742=0.38742

d) Probability that exactly 4 has neither cats or dogs (p=0.5)

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8 0
3 years ago
A waitress sold 11 ribeye steak dinners and 12 grilled salmon​ dinners, totaling ​$560.63 on a particular day. Another day she s
Eduardwww [97]

The cost of each ribeye steak dinner is $ 29 and cost of each grilled salmon dinner is $ 20

<em><u>Solution:</u></em>

Let "a" be the cost of each ribeye steak dinners

Let "b" be the cost of each grilled salmon dinners

<em><u>A waitress sold 11 ribeye steak dinners and 12 grilled salmon​ dinners, totaling ​$560.63 on a particular day</u></em>

Thus we frame a equation as:

11 x cost of each ribeye steak dinners + 12 x cost of each grilled salmon dinners = 560.63

11 \times a + 12 \times b = 560.63

11a + 12b = 560.63 -------- eqn 1

<em><u>Another day she sold 16 ribeye steak dinners and 6 grilled salmon​ dinners, totaling ​$584.46</u></em>

Thus we frame a equation as:

16 x cost of each ribeye steak dinners + 6 x cost of each grilled salmon dinners = 584.46

16 \times a + 6 \times b = 584.46

16a + 6b = 584.46 ------------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

<em><u>Multiply eqn 2 by 2</u></em>

32a + 12b = 1168.92 ------- eqn 3

<em><u>Subtract eqn 1 from eqn 3</u></em>

32a + 12b = 1168.92

11a + 12b = 560.63

( - ) ----------------

21a = 1168.92 - 560.63

21a = 608.29

Divide both sides by 21

a = 28.96 \approx 29

<em><u>Substitute a = 29 in eqn 1</u></em>

11(29) + 12b = 560.63

319 + 12b = 560.63

12b = 560.63 - 319

12b = 214.63

Divide both sides by 12

b = 20.13 \approx 20

Thus cost of each ribeye steak dinner is $ 29 and cost of each grilled salmon dinner is $ 20

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Answer:

Only one person is in the stopped vehicle

Step-by-step explanation:

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