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goldenfox [79]
3 years ago
7

A cruise ship is currently 20 kilometers away from its port and is traveling away from the port at 5 kilometers per hour . The f

unction is y=5x +20 relates the number of kilometers y the ship will be from its port x hours from now. How far will the cruise ship be from its port 3.5 hours from now
Mathematics
1 answer:
Paladinen [302]3 years ago
7 0

Answer:

The ship will be 37.5\ km far from its port 3.5 hours from now

Step-by-step explanation:

Hi

The function is y=5x +20 relates the number of kilometers y the ship will be from its port x hours from now, it has a form y=vt+y_{0} \ where \ y\ is\ final\ distance\\v\ is\ velocity\ in\ km/h,\ t\ is\ time\\and\ y_{0}\ is\ initial\ distance.

As the function is clearly defined, we only have to evaluate it for x=3.5, so y(3.5)=5(3.5)+20=17.5+20=37.5 \ km is the distance between the cruise ship and its port after 3.5 hours.

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Which of the following is an equation of the line through (2,3) and (-1,-12)
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Answer:

y = 5x - 7

Step-by-step explanation:

Using the equation of a line with two points

y_2 - y_1 / x_2 - x_1 = y - y_1 / x - x_1

Giving two points

( -4 , 10)(16 , -2)

x_1 = -4

y_1 = 10

x_2 = 16

y_2 = -2

Using the above formula

y_2 - y_1 / x_2 - x_1 = y - y_1 / x - x_1

-12 - 3 / -1 - 2 = y - 3 / x - 2

-15/-3 = y - 3 /x - 2

Cross multiply

-15(x - 2) = -3(y - 3)

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-15x + 30 + 3y - 9 = 0

-15x +30 - 9 + 3y = 0

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3y = 15x - 21 ( following y = mx + C

Dividing through by 3 to find y

3y/3 = 15x -21 / 3

y = 15x - 21 / 3

We can still separate

y = 15x / 3 - 21/3

y = 5x - 7

Therefore, the equation of the line is

y = 5x - 7

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