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mash [69]
3 years ago
7

The equation of a circle centered at the orgin is x^2 + y^2 = 16. What is the radius of the circle

Mathematics
1 answer:
Yuri [45]3 years ago
7 0

Given:

The equation of the circle is:

x^2+y^2=16

To find:

The radius of the circle.

Solution:

The standard form of a circle is:

(x-h)^2+(y-k)^2=r^2              ...(i)

Where, (h,k) is the center and r is the radius.

We have,

x^2+y^2=16

In can be written as:

x^2+y^2=4^2                 ...(ii)

On comparing (i) and (ii), we get

h=0

k=0

r=4

Here, the center of the circle is the origin and the radius is equal to 4 units.

Therefore, the radius of the given circle is 4 units.

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VikaD [51]
Not sure why such an old question is showing up on my feed...

Anyway, let x=\tan^{-1}\dfrac43 and y=\sin^{-1}\dfrac35. Then we want to find the exact value of \cos(x-y).

Use the angle difference identity:

\cos(x-y)=\cos x\cos y+\sin x\sin y

and right away we find \sin y=\dfrac35. By the Pythagorean theorem, we also find \cos y=\dfrac45. (Actually, this could potentially be negative, but let's assume all angles are in the first quadrant for convenience.)

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4 years ago
HELP!!! solve the following system:<br>y = x + 3<br>3x + y = 19
MariettaO [177]
3x + (x+3) = 19
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y= x+3
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