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Mamont248 [21]
3 years ago
8

If you flipped the coin 10 times, how many times do you think it would land on heads?

Mathematics
1 answer:
Juliette [100K]3 years ago
8 0

<em>It honestly doesn't matter how many times you flip a coin or, "the coin", the chance of the coin landing on heads, or tails will always be 50/50. </em>

<em>Echy~</em>

You might be interested in
Quadrilateral ABCD has vertices A(1, -3) , B(2, 1), C(6, 3), and D(7, -1). Prove or disprove that the Quad ABCD is a rectangle.
zavuch27 [327]
If AC=BD, than Quad ABCD is a rectangle
AC
√(3+3)²+(6-1)²
√6²+5²
√36+25
√61
BD
√(1+1)²+(2-7)²
√2²+(-5)²
√4+25
√29
Quad ABCD is not a rectangle because √61 and √29 are not equal.
7 0
3 years ago
Pls help I don't understand this
Rudiy27
<h3>Answer:</h3>

<u>By angle bisector property</u>,

  • 11x + 23 = 8x + 35
  • 11x - 8x = 35 - 23
  • 3x = 12
  • x = 4°

So, <u>m∠ABD</u> = 8x + 35

  • 8 × 4 + 35
  • 32 + 35 = 67°

<u>m∠CBD</u> = 11x + 23

  • 11 × 4 + 23
  • 44 + 23 = 67°

<u>m∠ABC</u> = 67° + 67° = 134°

4 0
3 years ago
3. Let X = {0,1,2,3,4,5)
erica [24]

Answer:

Answer for A

Step-by-step explanation:

I don't know about B , Sorry for that.

7 0
3 years ago
Read 2 more answers
Which of the following expressions are equivalent to x + y-z
gavmur [86]

Answer:

C since y-x are being subtracted and there should be another subtraction but there isnt

5 0
3 years ago
Arectangularplotoflandistobefencedinusingtwokinds of fencing. Two opposite sides will use heavy-duty fencing selling for $3 a fo
svlad2 [7]

Answer:

Dimensions of the rectangular plot will be 500 ft by 750 ft.

Step-by-step explanation:

Let the length of the rectangular plot = x ft.

and the width of the plot = y ft.

Cost to fence the length at the cost $3.00 per feet = 3x

Cost to fence the width of the cost $2.00 per feet = 2y

Total cost to fence all sides of rectangular plot = 2(3x + 2y)

2(3x + 2y) = 6,000

3x + 2y = 3,000 ----------(1)

3x + 2y = 3000

      2y = 3000 - 3x

      y = \frac{1}{2}[3000-3x]

      y = 1500 - \frac{3x}{2}

Now area of the rectangle A = xy square feet

A = x[1500-\frac{3x}{2}]

For maximum area \frac{dA}{dx}=0

A' = \frac{d}{dx}(1500x-\frac{3}{2}x^{2}) = 0

1500 - 3x = 0

3x = 1500

x = 500 ft

From equation (1),

y = 1500 - \frac{3}{2}\times 500

y = 1500 - 750

y = 750 ft

Therefore, for the maximum area of the rectangular plot will be 500 ft × 750 ft.

two fencing 3(500+500) = $3000

other two fencing 2(750+750) = $3000

8 0
3 years ago
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