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Romashka-Z-Leto [24]
3 years ago
8

Mike has 3 1/2 ounces of sugar to put in his coffee. If he actually only puts in 1 5/9 ounces of sugar, about how much sugar doe

s he have left? Estimating fractions.
PLZ HELP REEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
Mathematics
2 answers:
lana66690 [7]3 years ago
5 0

He would have exactly 1 \frac{17}{18} cups of sugar left.

Hope this helped. ^v^

elena55 [62]3 years ago
3 0

Answer:

I think it might be 1 17/18

(not sure)

Step-by-step explanation:

what I did was break down 3 1/2 and I got 2 3/2 I then Subtracted that by 1 5/9 (I don't know if it's right sorry if I'm wrong)

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-5/k=?/8k complete the expression
Nostrana [21]
?=-40 use -5/k)*(8k here u go
6 0
3 years ago
Read 2 more answers
△PQR is rotated 180° about the origin. What is the coordinate for Q' ?
oee [108]

Answer:

Part 1:

Q’ = (2, -3)

Part 2:

R’ = (-3, -4)

Hope this helps!

8 0
3 years ago
Please HElPPP I AM LITERALLY STUCK
Morgarella [4.7K]
Please see attached photo and give brainliest if you can :) it took me a looong time, hope it helped :)

7 0
3 years ago
If anyone knows this please help me. Please answer only if you know. Thanks! more points for you if answered!
Sauron [17]
1a) Possible rational roots will be of the form
  ±{divisor of 10}/{divisor of 4}
Divisors of 10 are {1, 2, 5, 10}
Divisors of 4 are {1, 2, 4}

Then possible rational roots are
  {±1/4, ±1/2, ±1, ±5/4, ±2, ±5/2, ±5, ±10}

1b) Your answer is correct.

2) One additional root will be the conjuate of the given complex root.
  5 -3i

3) If one root is 5 -√7, another will be 5 +√7. Then your polynomial is
  P(x) = (x -(5 -√7))*(x -(5 +√7)) = (x -5)^2 -(√7)^2
  P(x) = x^2 -10x +18
3 0
3 years ago
The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,
professor190 [17]

Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so \mu = 7*0.6 = 4.2

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150

P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630

P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323

So

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

3 0
3 years ago
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