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levacccp [35]
3 years ago
8

The volume of water and a rectangle swimming pool can be modeled by the function v(x)=x^3+13x-210. If the depth of the pool is g

iven by the expression x-3, what are the expressions that represent the width and length of the pool?
Mathematics
1 answer:
S_A_V [24]3 years ago
5 0

Answer:

Required,

L=\frac{3+\sqrt{37}}{2}-\frac{144}{x-3}

W=\frac{3-\sqrt{37}}{2}-\frac{144}{x-3}

Step-by-step explanation:

Given volume and depth respectively,

V(x)=x^3+13x-210 and x-3

To find length and width of the rectanglular swiming pool we know,

Volume=length\timesheight\timesdepth.

Let depth=D=x-3, length=L, width=W, then

V=DLW

x^3+13x-210= LW(x-3)

LW=\frac{x^3+13x-210}{x-3}

After divide we will get x^2-3x-22 with remainder -144.

Thus,

x^3+13x-210=(x^2-3x-22)(x-3)-144=(x-3)LW

Now to find root of,

x^2-3x-144=\frac{3\pm\sqrt{9+88}}{2}=\frac{3\pm \sqrt{37}}{2}

Thus,

L=\frac{3+\sqrt{37}}{2}-\frac{144}{x-3}

W=\frac{3-\sqrt{37}}{2}-\frac{144}{x-3}

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Step-by-step explanation:

Given

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So:

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r = 26

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The shade extends 4 inches beyond the window.

This means that;

The bottom length is now; Initial length + 8

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In (a), the length of each square is calculated as: 13in

4 squares make up the length and the height.

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Length = 4 * 13 + 8

Length = 60

Height = 4*13 + 4

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The radius of the semicircle becomes initial radius + 4

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The area is:

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The length of a rectangle is three times it’s width. The area of the rectangle is 48 square centimeters. Find the measures of th
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Define length and width
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Let the width be x
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Form equation and solve for x
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Width = x = 4
Length = 3x = 3(4) = 12

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Answer: Width = 4cm, Length = 12cm
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