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Gemiola [76]
3 years ago
15

What are the potential solutions of

Mathematics
1 answer:
densk [106]3 years ago
8 0

Answer:

I think it is x-2 and x=8

Hope it helps

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the ratio of the length to width in a full-size cello is approximately 8 to 3. What is the width of a full-size cello that is 45
Brut [27]

Answer:

w = 16.875 inches

Step-by-step explanation:

Given that the ratio of the length to width in a full-size cello is approximately 8 to 3.

This will be a constant for all cellos

Using the above we can find out length if we know width and vice versa.

Here we know the length = 45 inches

Since \frac{l}{w} =\frac{8}{3} =\frac{45}{w}

BY cross multiplication we find that

8w = 3(45)

Or w = 16.875 inches

Verify:

Let us check our answer by comparing with proportion

l/w = 45/16.875 = 8/3

Hence our answer is right

6 0
3 years ago
Read 2 more answers
Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Igoryamba
Hihi!

2/3 would be the right answer! Because 6 is 2/3 of 9.

I hope I helped!
-Jailbaitasmr
3 0
4 years ago
Find the area of the composite figure. round to the nearest tenth
katrin [286]
The correct answer to this is 70
3 0
3 years ago
During your cycling trip, you and your friends often stayed in hostels. The prices of these are listed below.
kiruha [24]

Answer:

  • a) NTRD standard price = $26.30
  • b) range: $11.20 to $33.00, a range of $21.80

Step-by-step explanation:

a) The average is the sum divided by the number of contributors. Let n represent the standard price at Night-Time Rest Days. Then ...

... ($22.45 +18.55 +24.50 +11.20 +n)/5 = $20.60

... 76.70 + n = 103.00 . . . . multiply by 5 and collect terms

... n = $26.30 . . . . standard price at NTRD

b) The lowest standard price is $11.20. The highest breakfast price is $33.00. The range is the difference between these ...

... $33.00 -11.20 = $21.80 . . . . range in cost for a single night

7 0
3 years ago
The angle θ lies in Quadrant II .
Andreyy89

let's keep in mind that, in the II Quadrant, cosine is negative and sine, is positive.

cosine is adjacent/hypotenuse, however the hypotenuse is simply a radius unit, and thus is never negative, so in the -(2/3) the negative must be the numerator, -2.


\bf cos(\theta )=\cfrac{\stackrel{adjacent}{-2}}{\stackrel{hypotenuse}{3}}\impliedby \textit{let's find the \underline{opposite side}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{3^2-(-2)^2}=b\implies \pm\sqrt{5}=b\implies \stackrel{\textit{II Quadrant}}{+\sqrt{5}=b}~\hfill tan(\theta )=\cfrac{\stackrel{opposite}{\sqrt{5}}}{\stackrel{adjacent}{-2}} \\\\\\ ~\hspace{34em}

6 0
4 years ago
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