There's an infinite number of equivalent fractions for 24/30 - all you need to do is to divide or multiple both numerator and denominator by the same number. For example:
24/30 = 48/60 (because 24 * 2 = 48 and 30 * 2 = 60)
24/30 = 12/15 (because 24 ÷ 2 = 12 and 30 ÷ 2 = 15)
24/30 = 72/90 (because 24 * 3 = 72 and 30 * 3 = 90)
24/30 = 4/5 (because 24 ÷ 6 = 4 and 30 ÷ 6 = 5)
etc...
<span>"Give an example of a sound financial decision Maura might make to support this goal. Why is it sound?"
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</span>She could choose to carefully budget her trip and avoid overspending at all costs. This prevents going into debt. She should also save up extra money in the event of an emergency.
</span><span>Then give an example of a poor financial decision Maura might make considering her goal. Why is it a poor decision?</span><span>
Not having a plan would be a poor decision on her part. She could end up spending too much and not realize how much money she has left.
I hope I helped!
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Answer:
Step-by-step explanation:
{0, 1, 2, 3, 4, ...} in set #1, addition by 1 , subtraction by -1, multiplication by 1 then addition of 1 or subtraction of -1, and division by one then addition of 1 or subtraction of -1 exist and are all well defined operations, since they yield the same result every time in a constant pattern (there are not the only examples)
{1, 3, 5, 7, ...} in set #2 addition by 2, subtraction by -2, multiplication by 1 then addition of 2 or subtraction of -2, and division by one then addition of 2 or subtraction of -2 exist and are all well defined operations, since they yield the same result every time in a constant pattern (there are not the only examples)
9514 1404 393
Answer:
no real solutions; k = ±i(2/3)√15
Step-by-step explanation:
If k is one of the roots, then substituting it for x will satisfy the equation:
k -4k -20/k = 0
Multiplying by k gives ...
-3k^2 -20 = 0
k^2 = -20/3 = -6 2/3
There are no real values of k such that this is true.
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If we allow k to be imaginary, then ...
k = ±i√(20/3) = ±i(2/3)√15
Possible imaginary values of k are ±(2/3)√15.