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ollegr [7]
2 years ago
6

Question 1

Mathematics
1 answer:
Sati [7]2 years ago
8 0

Answer:

152558.75*5%=7627.9

Step-by-step explanation:

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What’s standard form of y=6x-4
Natalija [7]

Answer: probably y= -24


Step-by-step explanation:


5 0
3 years ago
How many 7-digit phone numbers are possible, assuming that the first digit can’t be a 0 or a 1? (b) re-solve (a), except now ass
sladkih [1.3K]
A. We are going to form 7 digit numbers from the set {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}

where the first digit cannot be 0 or 1.

so we have 8 choices for the 1. digit, and 10 choices for all the other 6 digits.

this means there are 8*10*10*10*10*10*10=8* 10^{6} possible numbers.

b.

consider the numbers which start with 911. There are 10*10*10*10=10 ^{4} such numbers, since for the 4th, 5th, 6th and 7th digits we have 10 choices.

then we remove this number, from the one we found in a:

There are in total 8* 10^{6}-10^{4}=7,990,000 numbers which don't start with 911.


Answer:

a.8*10^{6}
b.7,990,000

3 0
3 years ago
Which graph represents a function?
lisabon 2012 [21]

Answer:

the bottom graph in the first photo

Step-by-step explanation:

it is a function, unlike the others, because that graph is the only one where the x values dont repeat. in order for it to be a function, the x values cannot repeat

3 0
3 years ago
Multiples of 3 are always multiples of 6.
Elena L [17]

Answer:yes 3x2=6

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Please help very urgent
Alik [6]

Answer:

32, <u>16</u>, <u>8</u>, <u>4</u>, <u>2</u>, 1

Explanation:

The geometric mean can be represented by \sqrt[n]{x_{1} • x_{2} • x_{3} • .. x_{n}}.

Which is the mean of the product of n numbers, used to find the average of a geometric progression.

Don't get confused by geometric mean, it is only asking you about the next numbers in the geometric sequence given the first and sixth term.

The explicit rule for a geometric sequence can be modeled by:

a_{n} = a_{1} • r^{n-1}

Where a_{n} is the nth term, a_{1} is the first term in the sequence, n is the term number, and r is the common ratio.

Since we already know the first term, a_{1} will simply be 32.

Since we know it's geometric, there will be an exponential relationship, which means that we will use the geometric mean to find the common ratio.

There are 6 total terms, r is raised to the n – 1 so 6 – 1 = 5, and that will be the degree of this root.

\sqrt[5]{\frac{a_{6}}{a_{1}}} =

\sqrt[5]{\frac{1}{32}} =

\frac{1}{2}.

Therefore: r = \frac{1}{2}.

Using all the information we have, we can find the explicit rule:

a_{n} = a_{1} • r^{n-1}

  • a_{1} = 32
  • r = \frac{1}{2}

a_{n} = a_{1} • r^{n-1} →

\boxed{a_{n} = 32 • (\frac{1}{2})^{n-1}}

________________________________

We can test that this works by substituting the number location of the term you want to find.

For instance:

a_{1} = 32 • (\frac{1}{2})^{1-1}

a_{1} = 32 • (\frac{1}{2})^{0}

a_{1} = 32 • 1

a_{1} = 32

a_{6} = 32 • (\frac{1}{2})^{6-1}

a_{6} = 32 • (\frac{1}{2})^{5}

a_{6} = 32 • \frac{1}{32}

a_{6} = 1

3 0
3 years ago
Read 2 more answers
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