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2 years ago

9

A S A P ! ! ! ! I nEEd help again!!

1 answer:

atroni [7]2 years ago

6 0

Answer:

3.00 feet

Step-by-step explanation:

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A pyramid of volume 344 square units is sliced into two pieces by a plane parallel to the base of the pyramid and 10 units away

Tom [10]

Answer:

80 units

Step-by-step explanation:

v = 1/3 bh

v₁ = 1/3 * b * h₁ = 344

v₂ = 1/3 * b * h₂ = 301

v₁ / v₂ = h₁ / h₂ = 344 / 301

h₂ = h₁ - 10

h₁ / (h₁ - 10) = 344 / 301

344 * (h₁ - 10) = 301 * h₁

344* h₁ - 3440 = 301 * h₁

43 * h₁ = 3440

h₁ = 80

4 0

2 years ago

A one-tailed test is a a. hypothesis test in which rejection region is in one tail of the sampling distribution b. hypothesis te

garri49 [273]

Answer:

Option A) One tailed test is a hypothesis test in which rejection region is in one tail of the sampling distribution

Step-by-step explanation:

One Tailed Test:

A one tailed test is a test that have hypothesis of the form

$H_0: \bar{x} = \mu\\H_A: \bar{x} < \mu\text{ or } \bar{x} > \mu$

A one-tailed test is a hypothesis test that help us to test whether the sample mean would be higher or lower than the population mean.
Rejection region is the area for which the null hypothesis is rejected.
If we perform right tailed hypothesis that is the upper tail hypothesis then the rejection region lies in the right tail after the critical value.

If we perform left tailed hypothesis that is the lower tail hypothesis then the rejection region lies in the left tail after the critical value.

Thus, for one tailed test,

Option A) One tailed test is a hypothesis test in which rejection region is in one tail of the sampling distribution

6 0

2 years ago

What is the solution to this system

KonstantinChe [14]

Answer:

The answer is (2,3)

Step-by-step explanation:

5 0

2 years ago

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

2 years ago

What is a rectangular prism with a surface area of 96 square meters

goldenfox [79]

If you're asking for the measurements, they are...

Length (l) = 4 ft.
Width (w) = 4 ft.
Height (h) = 4 ft.

8 0

2 years ago

Read 2 more answers