Answer:
A1 / B1 ;
(D1 - A1) / B1 ;
(A1 - E1*A1) / B1
Step-by-step explanation:
A1 = original price of car
B1 = annual Depreciation amount
Number of years it will take for the car to depreciate totally :
Using the straight line Depreciation relation :
y = mx + c
c = intercept = initial or original value of car
m = annual Depreciation amount
x = number of years
y = value after x years
For total Depreciation, final value, y = 0
0 = mx + c
mx = - c
x = - c / m
Hence, x = A1 / B1
B.)
D1 = car value
Length it will take for car to depreciate to value in D1 :
y = mx + c
y = D1; m = B1 ; c = A1
D1 = B1x + A1
B1x = D1 - A1
x = (D1 - A1) / B1
C.)
E1 = decrease percentage
Time it takes for car to decrease by percentage in E1
y = E1 * A1
E1 * A1 = B1x + A1
(A1 - E1*A1) = B1x
x = (A1 - E1*A1) / B1
∛(-45) = ∛((-1) × 45) = ∛(-1) × ∛45 = -∛45
Similarly,
∛(-101) = - ∛101
Now,
• 3³ = 27 and 4³ = 64, and 27 < 46 < 64, so ∛27 < ∛45 < ∛64, which places ∛45 between 3 and 4
• 5³ = 125, so ∛101 would similarly fall between 4 and 5
So to summarize, we have
3 < ∛45 < 4 < ∛101 < 5
so that
-5 < ∛(-45) < -4 < ∛(-101) < -3
so the integer between these numbers is -4.
The slope is -3 I’m not sure about the intercept
Answer:
+2
Step-by-step explanation:
=> 
=> 
<em>Arranging it in descending order</em>
=> 
<u><em>So, the coefficient of x² in this expression is +2</em></u>
Answer:
There were 210 downloads of the standard version.
Step-by-step explanation:
This question can be solved using a system of equations.
I am going to say that:
x is the number of downloads of the standard version.
y is the number of downloads of the high-quality version.
The size of the standard version is 2.6 megabytes (MB). The size of the high-quality version is 4.2 MB. The total size downloaded for the two versions was 4074 MB.
This means that:
Yesterday, the high-quality version was downloaded four times as often as the standard version.
This means that 
How many downloads of the standard version were there?
This is x.
Since
There were 210 downloads of the standard version.
