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3 years ago

PLEASE HELP I ATTACHED THE PICTURE

Mathematics

2 answers:

Andrei [34K]3 years ago

7 0

Answer:

option 3 is correct

Step-by-step explanation:

because ....

Jet001 [13]3 years ago

5 0

It has to be Option 3/C

Exlaination: I have done this problem before and got it right.

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15x ( 7 - 5y ) + 3 ( 5y - x ) - ( 4x + 3 ) ( 5y - 2 )

Sedbober [7]

15x ( 7 - 5y) + 3 ( 5y - x) - ( 4x + 3) (5y - 2) = -95xy + 110x + 6 is your solution hope it helps :)!

4 0

2 years ago

Read 2 more answers

Please!!! Help!!! Brainliest of Right! it goes as 50 point in the end but i used 100 point if you help me i will help you!!

vekshin1

Answer:

2. 3.913 kg (3 dp)

3. light cream

4. 240 CoffeeStops

5. 7 CoffeeStops per square mile

6. 2,861 cups of coffee each day

Step-by-step explanation:

Given:

Skim milk density at 20 °C = 1.033 kg/l
Light cream density at 20 °C = 1.012 kg/l
1 liter = 0.264 gallons

Question 2

$\begin{aligned}\textsf{1 gallon} & = \sf \dfrac{1}{0.264}\:liters\\\\\implies \textsf{Mass (1 gallon of skim milk)} & = \sf Density \times Volume\\& = \sf 1.033\:kg/l \times \dfrac{1}{0.264}\:l\\& = \sf 3.913\:kg\:(3\:dp)\end{aligned}$

Therefore, the mass of 1 gallon of skim milk is 3.913 kg (3 dp)

---------------------------------------------------------------------------------------------

Question 3

Given:

Volume of liquid = 9 liters
Mass of liquid = 9.108 kg

$\begin{aligned}\implies \sf Density & = \sf \dfrac{Mass}{Volume}\\\\& = \sf \dfrac{9.108\:kg}{9\:l}\\\\& = \sf 1.012\:kg/l \end{alilgned}$

Therefore, the container holds light cream.

---------------------------------------------------------------------------------------------

Question 4

Given:

15 CoffeeStops per 100,000 people
Population of Manhattan ≈ 1,602,000 people

$\begin{aligned}\implies \textsf{Number of Coffeestops} & = \sf \dfrac{population}{density}\\\\& = \sf \dfrac{1,602,000}{100,000/15}\\\\& = \sf \dfrac{1,602,000}{100,000} \times 15\\\\& = \sf 240.3\end{aligned}$

Therefore, there are 240 CoffeeStops.

---------------------------------------------------------------------------------------------

Question 5

Given

Manhattan ≈ 34 square miles

$\begin{aligned}\implies \textsf{CoffeeStops density} & = \sf \dfrac{number\:of\:stores}{land\:area}\\\\& = \sf \dfrac{240}{34}\\\\& \approx \sf 7 \: \textsf{CoffeeStops per square mile}\end{aligned}$

Therefore, the density of CoffeeStops is 7 per square mile.

---------------------------------------------------------------------------------------------

Question 6

Given:

Each person buys 3 cups of coffee per week

$\begin{aligned}\implies \textsf{Cups served each week} & = \textsf{number of people} \times \textsf{number of cups per week}\\& = \sf 1,602,000 \times 3\\& = \sf 4,806,000\: \textsf{cups per week}\\\\\implies \textsf{Cups per day} & = \sf \dfrac{\textsf{cups per week}}{\textsf{days in a week}}\\\\& = \sf \dfrac{4,806,000}{7}\\\\& = \sf 686,571\:\textsf{(nearest whole number)}\end{aligned}$

$\begin{aligned}\implies \textsf{Cups served per day per shop} & = \dfrac{\textsf{cups per day}}{\textsf{number of shops}}\\\\& = \sf \dfrac{686,571}{240}\\\\& = \sf 2,861\: \textsf{(nearest whole number)} \end{aligned}$

Therefore, each Manhattan CoffeeStop serves approximately 2,861 cups of coffee each day.

7 0

3 years ago

Complete this sentence: in a triangle, the angle with the smallest measure is always opposite the

Marta_Voda [28]

Answer:

Complete this sentence: in a triangle, the angle with the smallest measure is always opposite the shortest side.

8 0

3 years ago

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Find the solution of the inequality of b > 11.3

Tems11 [23]

The solution is the interval b is in ]11.3, infinity[

4 0

4 years ago

Fred has 30 minutes to do a three-problem quiz. He spent 10 7/10 minutes on question a and 5 2/5 minutes on question b. How much

tatiyna

Answer:Fred has 13 9/10 minutes left for question C

Step-by-step explanation:

The total time that Fred has to do the three-problem quiz is 30 minutes.

He spent 10 7/10 minutes on question A. Converting 10 7/10 minutes to improper fraction, it becomes 107/10 minutes.

He spent 5 2/5 minutes on question B. Converting 5 2/5 minutes to improper fraction, it becomes 27/5 minutes.

Total time that Fred spent on question A and question B is

107/10 + 27/5 = (107 + 54)/10

= 161/10 minutes.

The amount of time that he has left for question C would be

30 - 161/10 = (300 - 161)/10 = 139/10

= 13 9/10 minutes

3 0

3 years ago